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sched: Optimize build_sched_domains() for saving first SD node for a cpu
We are saving first scheduling domain for a cpu in build_sched_domains() by iterating over the nested sd->child list. We don't actually need to do it this way. tl will be equal to sched_domain_topology for the first iteration and so we can set *per_cpu_ptr(d.sd, i) based on that. So, save pointer to first SD while running the iteration loop over tl's. Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org> Signed-off-by: Peter Zijlstra <peterz@infradead.org> Link: http://lkml.kernel.org/r/fc473527cbc4dfa0b8eeef2a59db74684eb59a83.1370436120.git.viresh.kumar@linaro.org Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -5985,16 +5985,13 @@ static int build_sched_domains(const struct cpumask *cpu_map,
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sd = NULL;
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for (tl = sched_domain_topology; tl->init; tl++) {
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sd = build_sched_domain(tl, cpu_map, attr, sd, i);
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if (tl == sched_domain_topology)
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*per_cpu_ptr(d.sd, i) = sd;
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if (tl->flags & SDTL_OVERLAP || sched_feat(FORCE_SD_OVERLAP))
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sd->flags |= SD_OVERLAP;
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if (cpumask_equal(cpu_map, sched_domain_span(sd)))
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break;
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}
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while (sd->child)
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sd = sd->child;
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*per_cpu_ptr(d.sd, i) = sd;
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}
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/* Build the groups for the domains */
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