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hpet: Use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; struct boo entry[]; }; size = sizeof(struct foo) + count * sizeof(struct boo); instance = kzalloc(size, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); Notice that, in this case, variable siz is not necessary, hence it is removed. This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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@ -842,7 +842,6 @@ int hpet_alloc(struct hpet_data *hdp)
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struct hpet_dev *devp;
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u32 i, ntimer;
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struct hpets *hpetp;
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size_t siz;
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struct hpet __iomem *hpet;
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static struct hpets *last;
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unsigned long period;
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@ -860,10 +859,8 @@ int hpet_alloc(struct hpet_data *hdp)
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return 0;
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}
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siz = sizeof(struct hpets) + ((hdp->hd_nirqs - 1) *
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sizeof(struct hpet_dev));
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hpetp = kzalloc(siz, GFP_KERNEL);
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hpetp = kzalloc(struct_size(hpetp, hp_dev, hdp->hd_nirqs - 1),
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GFP_KERNEL);
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if (!hpetp)
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return -ENOMEM;
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