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memcg: memcg_kmem_create_cache: make memcg_name_buf statically allocated
It isn't worth complicating the code by allocating it on the first access, because it only takes 256 bytes. Signed-off-by: Vladimir Davydov <vdavydov@parallels.com> Cc: Michal Hocko <mhocko@suse.cz> Cc: Johannes Weiner <hannes@cmpxchg.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -3135,7 +3135,8 @@ void memcg_free_cache_params(struct kmem_cache *s)
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static void memcg_kmem_create_cache(struct mem_cgroup *memcg,
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struct kmem_cache *root_cache)
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{
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static char *memcg_name_buf; /* protected by memcg_slab_mutex */
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static char memcg_name_buf[NAME_MAX + 1]; /* protected by
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memcg_slab_mutex */
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struct kmem_cache *cachep;
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int id;
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@ -3151,12 +3152,6 @@ static void memcg_kmem_create_cache(struct mem_cgroup *memcg,
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if (cache_from_memcg_idx(root_cache, id))
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return;
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if (!memcg_name_buf) {
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memcg_name_buf = kmalloc(NAME_MAX + 1, GFP_KERNEL);
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if (!memcg_name_buf)
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return;
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}
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cgroup_name(memcg->css.cgroup, memcg_name_buf, NAME_MAX + 1);
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cachep = kmem_cache_create_memcg(memcg, root_cache, memcg_name_buf);
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/*
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