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memblock: Reimplement memblock_enforce_memory_limit() using __memblock_remove()
With recent updates, the basic memblock operations are robust enough that there's no reason for memblock_enfore_memory_limit() to directly manipulate memblock region arrays. Reimplement it using __memblock_remove(). Signed-off-by: Tejun Heo <tj@kernel.org> Cc: Benjamin Herrenschmidt <benh@kernel.crashing.org> Cc: Yinghai Lu <yinghai@kernel.org>
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@ -804,44 +804,28 @@ phys_addr_t __init_memblock memblock_end_of_DRAM(void)
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/* You must call memblock_analyze() after this. */
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void __init memblock_enforce_memory_limit(phys_addr_t memory_limit)
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void __init memblock_enforce_memory_limit(phys_addr_t limit)
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{
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unsigned long i;
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phys_addr_t limit;
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struct memblock_region *p;
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phys_addr_t max_addr = (phys_addr_t)ULLONG_MAX;
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if (!memory_limit)
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if (!limit)
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return;
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/* Truncate the memblock regions to satisfy the memory limit. */
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limit = memory_limit;
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/* find out max address */
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for (i = 0; i < memblock.memory.cnt; i++) {
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if (limit > memblock.memory.regions[i].size) {
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limit -= memblock.memory.regions[i].size;
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continue;
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}
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struct memblock_region *r = &memblock.memory.regions[i];
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memblock.memory.regions[i].size = limit;
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memblock.memory.cnt = i + 1;
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break;
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if (limit <= r->size) {
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max_addr = r->base + limit;
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break;
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}
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limit -= r->size;
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}
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memory_limit = memblock_end_of_DRAM();
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/* And truncate any reserves above the limit also. */
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for (i = 0; i < memblock.reserved.cnt; i++) {
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p = &memblock.reserved.regions[i];
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if (p->base > memory_limit)
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p->size = 0;
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else if ((p->base + p->size) > memory_limit)
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p->size = memory_limit - p->base;
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if (p->size == 0) {
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memblock_remove_region(&memblock.reserved, i);
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i--;
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}
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}
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/* truncate both memory and reserved regions */
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__memblock_remove(&memblock.memory, max_addr, (phys_addr_t)ULLONG_MAX);
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__memblock_remove(&memblock.reserved, max_addr, (phys_addr_t)ULLONG_MAX);
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}
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static int __init_memblock memblock_search(struct memblock_type *type, phys_addr_t addr)
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