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Btrfs: more efficient split extent state insertion
When we split an extent state there's no need to start the rbtree search from the root node - we can start it from the original extent state node, since we would end up in its subtree if we do the search starting at the root node anyway. Signed-off-by: Filipe David Borba Manana <fdmanana@gmail.com> Signed-off-by: Josef Bacik <jbacik@fb.com>
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f2071b2155
@ -229,12 +229,14 @@ void free_extent_state(struct extent_state *state)
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}
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}
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static struct rb_node *tree_insert(struct rb_root *root, u64 offset,
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static struct rb_node *tree_insert(struct rb_root *root,
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struct rb_node *search_start,
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u64 offset,
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struct rb_node *node,
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struct rb_node ***p_in,
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struct rb_node **parent_in)
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{
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struct rb_node **p = &root->rb_node;
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struct rb_node **p;
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struct rb_node *parent = NULL;
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struct tree_entry *entry;
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@ -244,6 +246,7 @@ static struct rb_node *tree_insert(struct rb_root *root, u64 offset,
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goto do_insert;
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}
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p = search_start ? &search_start : &root->rb_node;
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while (*p) {
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parent = *p;
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entry = rb_entry(parent, struct tree_entry, rb_node);
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@ -430,7 +433,7 @@ static int insert_state(struct extent_io_tree *tree,
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set_state_bits(tree, state, bits);
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node = tree_insert(&tree->state, end, &state->rb_node, p, parent);
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node = tree_insert(&tree->state, NULL, end, &state->rb_node, p, parent);
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if (node) {
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struct extent_state *found;
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found = rb_entry(node, struct extent_state, rb_node);
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@ -477,8 +480,8 @@ static int split_state(struct extent_io_tree *tree, struct extent_state *orig,
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prealloc->state = orig->state;
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orig->start = split;
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node = tree_insert(&tree->state, prealloc->end, &prealloc->rb_node,
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NULL, NULL);
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node = tree_insert(&tree->state, &orig->rb_node, prealloc->end,
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&prealloc->rb_node, NULL, NULL);
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if (node) {
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free_extent_state(prealloc);
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return -EEXIST;
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