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kcov: simplify interrupt check
in_interrupt() semantics are confusing and wrong for most users as it also returns true when bh is disabled. Thus we open coded a proper check for interrupts in __sanitizer_cov_trace_pc() with a lengthy explanatory comment. Use the new in_task() predicate instead. Link: http://lkml.kernel.org/r/20170321091026.139655-1-dvyukov@google.com Signed-off-by: Dmitry Vyukov <dvyukov@google.com> Cc: Kefeng Wang <wangkefeng.wang@huawei.com> Cc: James Morse <james.morse@arm.com> Cc: Alexander Popov <alex.popov@linux.com> Cc: Andrey Konovalov <andreyknvl@google.com> Cc: Hillf Danton <hillf.zj@alibaba-inc.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -60,15 +60,8 @@ void notrace __sanitizer_cov_trace_pc(void)
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/*
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* We are interested in code coverage as a function of a syscall inputs,
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* so we ignore code executed in interrupts.
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* The checks for whether we are in an interrupt are open-coded, because
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* 1. We can't use in_interrupt() here, since it also returns true
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* when we are inside local_bh_disable() section.
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* 2. We don't want to use (in_irq() | in_serving_softirq() | in_nmi()),
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* since that leads to slower generated code (three separate tests,
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* one for each of the flags).
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*/
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if (!t || (preempt_count() & (HARDIRQ_MASK | SOFTIRQ_OFFSET
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| NMI_MASK)))
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if (!t || !in_task())
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return;
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mode = READ_ONCE(t->kcov_mode);
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if (mode == KCOV_MODE_TRACE) {
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