2018-02-16 01:36:50 +00:00
|
|
|
/* -*- Mode: C++; tab-width: 8; indent-tabs-mode: nil; c-basic-offset: 2 -*- */
|
|
|
|
/* vim: set ts=8 sts=2 et sw=2 tw=80: */
|
|
|
|
/* This Source Code Form is subject to the terms of the Mozilla Public
|
|
|
|
* License, v. 2.0. If a copy of the MPL was not distributed with this
|
|
|
|
* file, You can obtain one at http://mozilla.org/MPL/2.0/. */
|
|
|
|
|
|
|
|
/*
|
2018-03-12 19:56:39 +00:00
|
|
|
* Math operations that implement wraparound semantics on overflow or underflow.
|
|
|
|
*
|
|
|
|
* While in some cases (but not all of them!) plain old C++ operators and casts
|
|
|
|
* will behave just like these functions, there are three reasons you should use
|
|
|
|
* these functions:
|
|
|
|
*
|
|
|
|
* 1) These functions make *explicit* the desire for and dependence upon
|
|
|
|
* wraparound semantics, just as Rust's i32::wrapping_add and similar
|
|
|
|
* functions explicitly produce wraparound in Rust.
|
|
|
|
* 2) They implement this functionality *safely*, without invoking signed
|
|
|
|
* integer overflow that has undefined behavior in C++.
|
|
|
|
* 3) They play nice with compiler-based integer-overflow sanitizers (see
|
2024-06-18 14:44:40 +00:00
|
|
|
* build/moz.configure/toolchain.configure), that in appropriately
|
|
|
|
* configured builds verify at runtime that integral arithmetic doesn't
|
|
|
|
* overflow.
|
2018-02-16 01:36:50 +00:00
|
|
|
*/
|
|
|
|
|
|
|
|
#ifndef mozilla_WrappingOperations_h
|
|
|
|
#define mozilla_WrappingOperations_h
|
|
|
|
|
|
|
|
#include "mozilla/Attributes.h"
|
|
|
|
|
|
|
|
#include <limits.h>
|
2020-03-28 13:57:11 +00:00
|
|
|
#include <type_traits>
|
2018-02-16 01:36:50 +00:00
|
|
|
|
|
|
|
namespace mozilla {
|
|
|
|
|
|
|
|
namespace detail {
|
|
|
|
|
|
|
|
template <typename UnsignedType>
|
|
|
|
struct WrapToSignedHelper {
|
2020-03-28 13:57:14 +00:00
|
|
|
static_assert(std::is_unsigned_v<UnsignedType>,
|
2018-02-16 01:36:50 +00:00
|
|
|
"WrapToSigned must be passed an unsigned type");
|
|
|
|
|
2020-03-28 13:57:11 +00:00
|
|
|
using SignedType = std::make_signed_t<UnsignedType>;
|
2018-02-16 01:36:50 +00:00
|
|
|
|
|
|
|
static constexpr SignedType MaxValue =
|
|
|
|
(UnsignedType(1) << (CHAR_BIT * sizeof(SignedType) - 1)) - 1;
|
|
|
|
static constexpr SignedType MinValue = -MaxValue - 1;
|
|
|
|
|
|
|
|
static constexpr UnsignedType MinValueUnsigned =
|
|
|
|
static_cast<UnsignedType>(MinValue);
|
|
|
|
static constexpr UnsignedType MaxValueUnsigned =
|
|
|
|
static_cast<UnsignedType>(MaxValue);
|
|
|
|
|
|
|
|
// Overflow-correctness was proven in bug 1432646 and is explained in the
|
|
|
|
// comment below. This function is very hot, both at compile time and
|
|
|
|
// runtime, so disable all overflow checking in it.
|
|
|
|
MOZ_NO_SANITIZE_UNSIGNED_OVERFLOW
|
|
|
|
MOZ_NO_SANITIZE_SIGNED_OVERFLOW static constexpr SignedType compute(
|
|
|
|
UnsignedType aValue) {
|
|
|
|
// This algorithm was originally provided here:
|
|
|
|
// https://stackoverflow.com/questions/13150449/efficient-unsigned-to-signed-cast-avoiding-implementation-defined-behavior
|
|
|
|
//
|
|
|
|
// If the value is in the non-negative signed range, just cast.
|
|
|
|
//
|
|
|
|
// If the value will be negative, compute its delta from the first number
|
|
|
|
// past the max signed integer, then add that to the minimum signed value.
|
|
|
|
//
|
|
|
|
// At the low end: if |u| is the maximum signed value plus one, then it has
|
|
|
|
// the same mathematical value as |MinValue| cast to unsigned form. The
|
|
|
|
// delta is zero, so the signed form of |u| is |MinValue| -- exactly the
|
|
|
|
// result of adding zero delta to |MinValue|.
|
|
|
|
//
|
|
|
|
// At the high end: if |u| is the maximum *unsigned* value, then it has all
|
|
|
|
// bits set. |MinValue| cast to unsigned form is purely the high bit set.
|
|
|
|
// So the delta is all bits but high set -- exactly |MaxValue|. And as
|
|
|
|
// |MinValue = -MaxValue - 1|, we have |MaxValue + (-MaxValue - 1)| to
|
|
|
|
// equal -1.
|
|
|
|
//
|
|
|
|
// Thus the delta below is in signed range, the corresponding cast is safe,
|
|
|
|
// and this computation produces values spanning [MinValue, 0): exactly the
|
|
|
|
// desired range of all negative signed integers.
|
|
|
|
return (aValue <= MaxValueUnsigned)
|
|
|
|
? static_cast<SignedType>(aValue)
|
|
|
|
: static_cast<SignedType>(aValue - MinValueUnsigned) + MinValue;
|
|
|
|
}
|
|
|
|
};
|
|
|
|
|
|
|
|
} // namespace detail
|
|
|
|
|
|
|
|
/**
|
|
|
|
* Convert an unsigned value to signed, if necessary wrapping around.
|
|
|
|
*
|
|
|
|
* This is the behavior normal C++ casting will perform in most implementations
|
|
|
|
* these days -- but this function makes explicit that such conversion is
|
|
|
|
* happening.
|
|
|
|
*/
|
|
|
|
template <typename UnsignedType>
|
2018-03-07 23:27:14 +00:00
|
|
|
constexpr typename detail::WrapToSignedHelper<UnsignedType>::SignedType
|
2018-02-16 01:36:50 +00:00
|
|
|
WrapToSigned(UnsignedType aValue) {
|
|
|
|
return detail::WrapToSignedHelper<UnsignedType>::compute(aValue);
|
|
|
|
}
|
|
|
|
|
2018-02-16 01:36:55 +00:00
|
|
|
namespace detail {
|
|
|
|
|
2018-03-12 19:56:39 +00:00
|
|
|
template <typename T>
|
2020-03-28 13:57:12 +00:00
|
|
|
constexpr T ToResult(std::make_unsigned_t<T> aUnsigned) {
|
2018-03-12 19:56:39 +00:00
|
|
|
// We could *always* return WrapToSigned and rely on unsigned conversion to
|
|
|
|
// undo the wrapping when |T| is unsigned, but this seems clearer.
|
2020-03-28 13:57:15 +00:00
|
|
|
return std::is_signed_v<T> ? WrapToSigned(aUnsigned) : aUnsigned;
|
2018-03-12 19:56:39 +00:00
|
|
|
}
|
|
|
|
|
2018-03-07 03:21:58 +00:00
|
|
|
template <typename T>
|
|
|
|
struct WrappingAddHelper {
|
|
|
|
private:
|
2020-03-28 13:57:12 +00:00
|
|
|
using UnsignedT = std::make_unsigned_t<T>;
|
2018-03-07 03:21:58 +00:00
|
|
|
|
|
|
|
public:
|
|
|
|
MOZ_NO_SANITIZE_UNSIGNED_OVERFLOW
|
2018-03-07 23:27:14 +00:00
|
|
|
static constexpr T compute(T aX, T aY) {
|
2018-03-12 19:56:39 +00:00
|
|
|
return ToResult<T>(static_cast<UnsignedT>(aX) + static_cast<UnsignedT>(aY));
|
2018-03-07 03:21:58 +00:00
|
|
|
}
|
|
|
|
};
|
|
|
|
|
|
|
|
} // namespace detail
|
|
|
|
|
|
|
|
/**
|
2018-03-12 19:56:39 +00:00
|
|
|
* Add two integers of the same type and return the result converted to that
|
|
|
|
* type using wraparound semantics, without triggering overflow sanitizers.
|
2018-03-07 03:21:58 +00:00
|
|
|
*
|
|
|
|
* For N-bit unsigned integer types, this is equivalent to adding the two
|
|
|
|
* numbers, then taking the result mod 2**N:
|
|
|
|
*
|
|
|
|
* WrappingAdd(uint32_t(42), uint32_t(17)) is 59 (59 mod 2**32);
|
|
|
|
* WrappingAdd(uint8_t(240), uint8_t(20)) is 4 (260 mod 2**8).
|
|
|
|
*
|
2018-03-12 19:56:39 +00:00
|
|
|
* Unsigned WrappingAdd acts exactly like C++ unsigned addition.
|
2018-03-07 03:21:58 +00:00
|
|
|
*
|
|
|
|
* For N-bit signed integer types, this is equivalent to adding the two numbers
|
2018-03-12 19:56:39 +00:00
|
|
|
* wrapped to unsigned, then wrapping the sum mod 2**N to the signed range:
|
2018-03-07 03:21:58 +00:00
|
|
|
*
|
|
|
|
* WrappingAdd(int16_t(32767), int16_t(3)) is
|
|
|
|
* -32766 ((32770 mod 2**16) - 2**16);
|
|
|
|
* WrappingAdd(int8_t(-128), int8_t(-128)) is
|
|
|
|
* 0 (256 mod 2**8);
|
|
|
|
* WrappingAdd(int32_t(-42), int32_t(-17)) is
|
|
|
|
* -59 ((8589934533 mod 2**32) - 2**32).
|
|
|
|
*
|
2018-03-12 19:56:39 +00:00
|
|
|
* There's no equivalent to this operation in C++, as C++ signed addition that
|
|
|
|
* overflows has undefined behavior. But it's how such addition *tends* to
|
|
|
|
* behave with most compilers, unless an optimization or similar -- quite
|
|
|
|
* permissibly -- triggers different behavior.
|
2018-03-07 03:21:58 +00:00
|
|
|
*/
|
|
|
|
template <typename T>
|
|
|
|
constexpr T WrappingAdd(T aX, T aY) {
|
|
|
|
return detail::WrappingAddHelper<T>::compute(aX, aY);
|
|
|
|
}
|
|
|
|
|
|
|
|
namespace detail {
|
|
|
|
|
2018-03-07 03:22:20 +00:00
|
|
|
template <typename T>
|
|
|
|
struct WrappingSubtractHelper {
|
|
|
|
private:
|
2020-03-28 13:57:12 +00:00
|
|
|
using UnsignedT = std::make_unsigned_t<T>;
|
2018-03-07 03:22:20 +00:00
|
|
|
|
|
|
|
public:
|
|
|
|
MOZ_NO_SANITIZE_UNSIGNED_OVERFLOW
|
2018-03-07 23:27:14 +00:00
|
|
|
static constexpr T compute(T aX, T aY) {
|
2018-03-07 03:22:20 +00:00
|
|
|
return ToResult<T>(static_cast<UnsignedT>(aX) - static_cast<UnsignedT>(aY));
|
|
|
|
}
|
|
|
|
};
|
|
|
|
|
|
|
|
} // namespace detail
|
|
|
|
|
|
|
|
/**
|
|
|
|
* Subtract two integers of the same type and return the result converted to
|
|
|
|
* that type using wraparound semantics, without triggering overflow sanitizers.
|
|
|
|
*
|
|
|
|
* For N-bit unsigned integer types, this is equivalent to subtracting the two
|
|
|
|
* numbers, then taking the result mod 2**N:
|
|
|
|
*
|
|
|
|
* WrappingSubtract(uint32_t(42), uint32_t(17)) is 29 (29 mod 2**32);
|
|
|
|
* WrappingSubtract(uint8_t(5), uint8_t(20)) is 241 (-15 mod 2**8).
|
|
|
|
*
|
|
|
|
* Unsigned WrappingSubtract acts exactly like C++ unsigned subtraction.
|
|
|
|
*
|
|
|
|
* For N-bit signed integer types, this is equivalent to subtracting the two
|
|
|
|
* numbers wrapped to unsigned, then wrapping the difference mod 2**N to the
|
|
|
|
* signed range:
|
|
|
|
*
|
|
|
|
* WrappingSubtract(int16_t(32767), int16_t(-5)) is -32764 ((32772 mod 2**16)
|
|
|
|
* - 2**16); WrappingSubtract(int8_t(-128), int8_t(127)) is 1 (-255 mod 2**8);
|
|
|
|
* WrappingSubtract(int32_t(-17), int32_t(-42)) is 25 (25 mod 2**32).
|
|
|
|
*
|
|
|
|
* There's no equivalent to this operation in C++, as C++ signed subtraction
|
|
|
|
* that overflows has undefined behavior. But it's how such subtraction *tends*
|
|
|
|
* to behave with most compilers, unless an optimization or similar -- quite
|
|
|
|
* permissibly -- triggers different behavior.
|
|
|
|
*/
|
|
|
|
template <typename T>
|
|
|
|
constexpr T WrappingSubtract(T aX, T aY) {
|
|
|
|
return detail::WrappingSubtractHelper<T>::compute(aX, aY);
|
|
|
|
}
|
|
|
|
|
|
|
|
namespace detail {
|
|
|
|
|
2018-02-16 01:36:55 +00:00
|
|
|
template <typename T>
|
|
|
|
struct WrappingMultiplyHelper {
|
|
|
|
private:
|
2020-03-28 13:57:12 +00:00
|
|
|
using UnsignedT = std::make_unsigned_t<T>;
|
2018-02-16 01:36:55 +00:00
|
|
|
|
|
|
|
public:
|
|
|
|
MOZ_NO_SANITIZE_UNSIGNED_OVERFLOW
|
2018-03-07 23:27:14 +00:00
|
|
|
static constexpr T compute(T aX, T aY) {
|
2018-03-12 19:56:39 +00:00
|
|
|
// Begin with |1U| to ensure the overall operation chain is never promoted
|
|
|
|
// to signed integer operations that might have *signed* integer overflow.
|
|
|
|
return ToResult<T>(static_cast<UnsignedT>(1U * static_cast<UnsignedT>(aX) *
|
|
|
|
static_cast<UnsignedT>(aY)));
|
2018-02-16 01:36:55 +00:00
|
|
|
}
|
|
|
|
};
|
|
|
|
|
|
|
|
} // namespace detail
|
|
|
|
|
|
|
|
/**
|
2018-03-12 19:56:39 +00:00
|
|
|
* Multiply two integers of the same type and return the result converted to
|
|
|
|
* that type using wraparound semantics, without triggering overflow sanitizers.
|
2018-02-16 01:36:55 +00:00
|
|
|
*
|
|
|
|
* For N-bit unsigned integer types, this is equivalent to multiplying the two
|
|
|
|
* numbers, then taking the result mod 2**N:
|
|
|
|
*
|
|
|
|
* WrappingMultiply(uint32_t(42), uint32_t(17)) is 714 (714 mod 2**32);
|
|
|
|
* WrappingMultiply(uint8_t(16), uint8_t(24)) is 128 (384 mod 2**8);
|
|
|
|
* WrappingMultiply(uint16_t(3), uint16_t(32768)) is 32768 (98304 mod 2*16).
|
|
|
|
*
|
2018-03-12 19:56:39 +00:00
|
|
|
* Unsigned WrappingMultiply is *not* identical to C++ multiplication: with most
|
|
|
|
* compilers, in rare cases uint16_t*uint16_t can invoke *signed* integer
|
|
|
|
* overflow having undefined behavior! http://kqueue.org/blog/2013/09/17/cltq/
|
|
|
|
* has the grody details. (Some compilers do this for uint32_t, not uint16_t.)
|
|
|
|
* So it's especially important to use WrappingMultiply for wraparound math with
|
|
|
|
* uint16_t. That quirk aside, this function acts like you *thought* C++
|
|
|
|
* unsigned multiplication always worked.
|
2018-02-16 01:36:55 +00:00
|
|
|
*
|
|
|
|
* For N-bit signed integer types, this is equivalent to multiplying the two
|
2018-03-12 19:56:39 +00:00
|
|
|
* numbers wrapped to unsigned, then wrapping the product mod 2**N to the signed
|
|
|
|
* range:
|
2018-02-16 01:36:55 +00:00
|
|
|
*
|
|
|
|
* WrappingMultiply(int16_t(-456), int16_t(123)) is
|
|
|
|
* 9448 ((-56088 mod 2**16) + 2**16);
|
|
|
|
* WrappingMultiply(int32_t(-7), int32_t(-9)) is 63 (63 mod 2**32);
|
|
|
|
* WrappingMultiply(int8_t(16), int8_t(24)) is -128 ((384 mod 2**8) - 2**8);
|
|
|
|
* WrappingMultiply(int8_t(16), int8_t(255)) is -16 ((4080 mod 2**8) - 2**8).
|
|
|
|
*
|
2018-03-12 19:56:39 +00:00
|
|
|
* There's no equivalent to this operation in C++, as C++ signed
|
|
|
|
* multiplication that overflows has undefined behavior. But it's how such
|
|
|
|
* multiplication *tends* to behave with most compilers, unless an optimization
|
|
|
|
* or similar -- quite permissibly -- triggers different behavior.
|
2018-02-16 01:36:55 +00:00
|
|
|
*/
|
|
|
|
template <typename T>
|
|
|
|
constexpr T WrappingMultiply(T aX, T aY) {
|
|
|
|
return detail::WrappingMultiplyHelper<T>::compute(aX, aY);
|
|
|
|
}
|
|
|
|
|
2018-02-16 01:36:50 +00:00
|
|
|
} /* namespace mozilla */
|
|
|
|
|
|
|
|
#endif /* mozilla_WrappingOperations_h */
|