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Bug 1216038 - Deduce underlying integer type for MakeEnumeratedRange starting at 0. r=froydnj

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This commit is contained in:
Cameron McCormack 2015-10-20 10:16:19 +11:00
parent c6deb98829
commit 4fa140ec32
1 changed files with 10 additions and 3 deletions
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13
mfbt/EnumeratedRange.h
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@ -171,6 +171,9 @@ private:
#endif
// Create a range to iterate from aBegin to aEnd, exclusive.
//
// (Once we can rely on std::underlying_type, we can remove the IntType
// template parameter.)
template<typename IntType, typename EnumType>
inline detail::EnumeratedRange<IntType, EnumType>
MakeEnumeratedRange(EnumType aBegin, EnumType aEnd)
@ -189,11 +192,15 @@ MakeEnumeratedRange(EnumType aBegin, EnumType aEnd)
// Create a range to iterate from EnumType(0) to aEnd, exclusive. EnumType(0)
// should exist, but note that there is no way for us to ensure that it does!
template<typename IntType, typename EnumType>
inline detail::EnumeratedRange<IntType, EnumType>
// Since the enumeration starts at EnumType(0), we know for sure that the values
// will be in range of our deduced IntType.
template<typename EnumType>
inline detail::EnumeratedRange<UnsignedStdintTypeForSize<sizeof(EnumType)>::Type,
EnumType>
MakeEnumeratedRange(EnumType aEnd)
{
return MakeEnumeratedRange<IntType>(EnumType(0), aEnd);
return MakeEnumeratedRange<UnsignedStdintTypeForSize<sizeof(EnumType)>::Type>(
EnumType(0), aEnd);
}
#ifdef __GNUC__