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bug 348731, check for default engine to be first, log that

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This commit is contained in:
axel%pike.org 2006-09-08 18:03:19 +00:00
parent 6944d8d3e1
commit cc9ca65fa0
1 changed files with 12 additions and 0 deletions
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12
testing/tests/l10n/lib/Mozilla/Tests.py
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@ -269,6 +269,8 @@ class SearchTest(Base):
m = re.match('browser.search.order.([1-9])', key)
if m:
orders[val.strip()] = int(m.group(1))
elif key == 'browser.search.defaultenginename':
sets[loc]['default'] = val.strip()
sets[loc]['orders'] = orders
for fn in lst:
name = fn.strip()
@ -306,7 +308,17 @@ class SearchTest(Base):
'''
for loc, val in myResult['locales'].iteritems():
l = logging.getLogger('locales.' + loc)
# Verify that there are no errors in the engine parsing,
# and that there default engine is the first one.
if (not val['orders'].has_key(val['default'])) or val['orders'][val['default']] != 1:
l.error('Default engine is not first in order')
if not failureResult.has_key(loc):
failureResult[loc] = 2
else:
failureResult[loc] |= 2
for p in val['list']:
# no logging, that is already reported above
if myResult['details'][p].has_key('error'):
if not failureResult.has_key(loc):
failureResult[loc] = 2