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136 lines
5.1 KiB
C++
136 lines
5.1 KiB
C++
/* This Source Code Form is subject to the terms of the Mozilla Public
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* License, v. 2.0. If a copy of the MPL was not distributed with this
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* file, You can obtain one at http://mozilla.org/MPL/2.0/. */
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#include <math.h>
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#include "nsGeoGridFuzzer.h"
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#include "nsGeoPosition.h"
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#ifdef MOZ_APPROX_LOCATION
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/* The following constants are taken from the World Geodetic System 1984 (WGS84)
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* reference model for the earth ellipsoid [1]. The values in the model are
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* an accepted standard for GPS and other navigational systems.
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*
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* [1] http://www.oosa.unvienna.org/pdf/icg/2012/template/WGS_84.pdf
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*/
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#define WGS84_a (6378137.0) // equitorial axis
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#define WGS84_b (6356752.314245179) // polar axis (a * (1-f))
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#define WGS84_f (1.0/298.257223563) // inverse flattening
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#define WGS84_EPSILON (5.72957795e-9) // 1e-10 radians in degrees
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#define sq(f) ((f) * (f))
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#define sign(f) (((f) < 0) ? -1 : 1)
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/* if you have an ellipsoid with semi-major axis A and semi-minor axis B, the
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* radius at angle phi along the semi-major axis can be calculated with this
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* formula. by using the WGS84 values for A and B, we calculate the radius of
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* earth, given the angle of latitude, phi.*/
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#define LON_RADIUS(phi) (sqrt((sq(sq(WGS84_a) * cos(phi)) + sq(sq(WGS84_b) * sin(phi))) / \
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(sq(WGS84_a * cos(phi)) + sq(WGS84_b * sin(phi)))))
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/* the radius of earth changes as a function of latitude, to simplify I am
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* assuming the fixed radius of the earth halfway between the poles and the
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* equator. this is calculated from LON_RADIUS(M_PI/4), or the radius at
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* 45 degrees N.*/
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#define LAT_RADIUS (6367489.543863)
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/* This function figures out the latitudinal grid square that the given
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* latitude coordinate falls into and then returns the latitudinal center of
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* that grid square. It handles the proper wrapping at the poles +/- 90
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* (e.g. +95 wraps to +85 and -95 wraps to -85) */
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static double GridAlgorithmLat(int32_t aDistMeters, double aLatDeg)
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{
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/* switch to radians */
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double phi = (aLatDeg * M_PI) / 180;
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/* properly wrap the latitude */
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phi = atan(sin(phi) / fabs(cos(phi)));
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/* calculate grid size in radians */
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double gridSizeRad = aDistMeters / LAT_RADIUS;
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/* find the southern edge, in radians, of the grid cell, then add half of a
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* grid cell to find the center latitude in radians */
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double gridCenterPhi = gridSizeRad * floor(phi / gridSizeRad) + gridSizeRad / 2;
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/* properly wrap it and return it in degrees */
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return atan(sin(gridCenterPhi) / fabs(cos(gridCenterPhi))) * (180.0 / M_PI);
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}
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/* This function figures out the longitudinal grid square that the given longitude
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* coordinate falls into and then returns the longitudinal center of that grid
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* square. It handles the proper wrapping at +/- 180 (e.g. +185 wraps to -175
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* and -185 wraps to +175) */
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static double GridAlgorithmLon(int32_t aDistMeters, double aLatDeg, double aLonDeg)
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{
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/* switch to radians */
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double phi = (aLatDeg * M_PI) / 180;
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double theta = (aLonDeg * M_PI) / 180;
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/* properly wrap the lat/lon */
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phi = atan(sin(phi) / fabs(cos(phi)));
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theta = atan2(sin(theta), cos(theta));
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/* calculate grid size in radians */
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double gridSizeRad = aDistMeters / LON_RADIUS(phi);
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/* find the western edge, in radians, of the grid cell, then add half of a
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* grid cell to find the center longitude in radians */
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double gridCenterTheta = gridSizeRad * floor(theta / gridSizeRad) + gridSizeRad / 2;
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/* properly wrap it and return it in degrees */
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return atan2(sin(gridCenterTheta), cos(gridCenterTheta)) * (180.0 / M_PI);
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}
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/* This function takes the grid size and the graticule coordinates of a
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* location and calculates which grid cell the coordinates fall within and
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* then returns the coordinates of the geographical center of the grid square.
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*/
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static void CalculateGridCoords(int32_t aDistKm, double& aLatDeg, double& aLonDeg)
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{
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// a grid size of 0 is the same as precise
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if (aDistKm == 0) {
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return;
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}
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aLonDeg = GridAlgorithmLon(aDistKm * 1000, aLatDeg, aLonDeg);
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aLatDeg = GridAlgorithmLat(aDistKm * 1000, aLatDeg);
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}
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already_AddRefed<nsIDOMGeoPosition>
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nsGeoGridFuzzer::FuzzLocation(const GeolocationSetting & aSetting,
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nsIDOMGeoPosition * aPosition)
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{
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if (!aPosition) {
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return nullptr;
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}
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nsCOMPtr<nsIDOMGeoPositionCoords> coords;
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nsresult rv = aPosition->GetCoords(getter_AddRefs(coords));
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NS_ENSURE_SUCCESS(rv, nullptr);
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if (!coords) {
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return nullptr;
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}
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double lat = 0.0, lon = 0.0;
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coords->GetLatitude(&lat);
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coords->GetLongitude(&lon);
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// adjust lat/lon to be the center of the grid square
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CalculateGridCoords(aSetting.GetApproxDistance(), lat, lon);
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GPSLOG("approximate location with delta %d is %f, %f",
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aSetting.GetApproxDistance(), lat, lon);
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// reusing the timestamp
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DOMTimeStamp ts;
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rv = aPosition->GetTimestamp(&ts);
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NS_ENSURE_SUCCESS(rv, nullptr);
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// return a position at sea level, N heading, 0 speed, 0 error.
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nsRefPtr<nsGeoPosition> pos = new nsGeoPosition(lat, lon, 0.0, 0.0,
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0.0, 0.0, 0.0, ts);
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return pos.forget();
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}
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#endif
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