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Don't hit an assertion failure when calculating the __PRETTY_FUNCTION__

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of a member function with parenthesized declarator.

Like this test case:

class Foo {
  const char *(baz)() {
    return __PRETTY_FUNCTION__;
  }
};

llvm-svn: 170233
This commit is contained in:
Argyrios Kyrtzidis 2012-12-14 19:44:11 +00:00
parent a40bcac0ef
commit 53e3d6d7f0
2 changed files with 2 additions and 2 deletions
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2
clang/lib/AST/Expr.cpp
View File

@ -510,7 +510,7 @@ std::string PredefinedExpr::ComputeName(IdentType IT, const Decl *CurrentDecl) {
POut << ")";
if (const CXXMethodDecl *MD = dyn_cast<CXXMethodDecl>(FD)) {
const FunctionType *FT = cast<FunctionType>(MD->getType().getTypePtr());
const FunctionType *FT = MD->getType()->castAs<FunctionType>();
if (FT->isConst())
POut << " const";
if (FT->isVolatile())

2
clang/test/CodeGenCXX/predefined-expr.cpp
View File

@ -142,7 +142,7 @@ public:
printf("__PRETTY_FUNCTION__ %s\n\n", __PRETTY_FUNCTION__);
}
inline void inlineFunction() {
inline void (inlineFunction)() {
printf("__func__ %s\n", __func__);
printf("__FUNCTION__ %s\n", __FUNCTION__);
printf("__PRETTY_FUNCTION__ %s\n\n", __PRETTY_FUNCTION__);