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Optimize std::midpoint for integers
Same idea as the current algorithm, that is, add (half of the difference between a and b) to a. But we use a different technique for computing the difference: we compute b - a into a pair of integers that are named "sign_bit" and "diff". We have to use a pair because subtracting two 32-bit integers produces a 33-bit result. Computing half of that is a simple matter of shifting diff right by 1, and adding sign_bit shifted left by 31. llvm knows how to do that with one instruction: shld. The only tricky part is that if the difference is odd and negative, then shifting it by one isn't the same as dividing it by two - shifting a negative one produces a negative one, for example. So there's one more adjustment: if the sign bit and the low bit of diff are one, we add one. For a demonstration of the codegen difference, see https://godbolt.org/z/7ar3K9 , which also has a built-in test. Differential Revision: https://reviews.llvm.org/D69459
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@ -532,17 +532,14 @@ midpoint(_Tp __a, _Tp __b) noexcept
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_LIBCPP_DISABLE_UBSAN_UNSIGNED_INTEGER_CHECK
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{
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using _Up = std::make_unsigned_t<_Tp>;
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constexpr _Up __bitshift = std::numeric_limits<_Up>::digits - 1;
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int __sign = 1;
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_Up __m = __a;
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_Up __M = __b;
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if (__a > __b)
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{
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__sign = -1;
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__m = __b;
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__M = __a;
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}
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return __a + __sign * _Tp(_Up(__M-__m) >> 1);
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_Up __diff = _Up(__b) - _Up(__a);
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_Up __sign_bit = __b < __a;
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_Up __half_diff = (__diff / 2) + (__sign_bit << __bitshift) + (__sign_bit & __diff);
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return __a + __half_diff;
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}
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