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[flang] Retain the sign of the argument for the result of fraction(0)
The f18 clause 16.9.80 description of the FRACTION(X) intrinsic states: Result Value. The result has the value .... If X has the value zero, the result is zero. If X is an IEEE NaN, the result is that NaN. If X is an IEEE infinity, the result is an IEEE NaN. This clause does not specify whether fraction(-0.0) should be -0.0 or +0.0. However, a folded result and a runtime result should be consistent, and returning -0.0 is more in line with the result for fraction(NaN). For this test: print '(2f6.1)', 0.0, fraction(0.0) call f(0.0) print '(2f6.1)', -0.0, fraction(-0.0) call f(-0.0) end subroutine f(x) print '(2f6.1)', x, fraction(x) end Current output is: 0.0 0.0 0.0 0.0 -0.0 -0.0 -0.0 0.0 Change that to: 0.0 0.0 0.0 0.0 -0.0 -0.0 -0.0 -0.0
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@ -83,7 +83,7 @@ template <typename T> inline T Fraction(T x) {
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} else if (std::isinf(x)) {
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return std::numeric_limits<T>::quiet_NaN(); // +/-Inf -> NaN
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} else if (x == 0) {
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return 0; // 0 -> 0
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return x; // 0 -> same 0
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} else {
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int ignoredExp;
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return std::frexp(x, &ignoredExp);
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