RNG: Take pass name as argument instead of pass pointer.

Summary: With the new pass manager, it is not possible to obtain a pointer to the pass.

Reviewers: jfb, rinon, yln

Subscribers: hiraditya, dexonsmith, llvm-commits

Tags: #llvm

Differential Revision: https://reviews.llvm.org/D73390

llvm/include/llvm/IR/Module.h

@@ -259,7 +259,7 @@ public:
   /// when other randomness consuming passes are added or removed. In
   /// addition, the random stream will be reproducible across LLVM
   /// versions when the pass does not change.
-  std::unique_ptr<RandomNumberGenerator> createRNG(const Pass* P) const;
+  std::unique_ptr<RandomNumberGenerator> createRNG(const StringRef Name) const;
 
   /// Return true if size-info optimization remark is enabled, false
   /// otherwise.

llvm/lib/IR/Module.cpp

@@ -86,8 +86,9 @@ Module::~Module() {
   IFuncList.clear();
 }
 
-std::unique_ptr<RandomNumberGenerator> Module::createRNG(const Pass* P) const {
+std::unique_ptr<RandomNumberGenerator>
-  SmallString<32> Salt(P->getPassName());
+Module::createRNG(const StringRef Name) const {
+  SmallString<32> Salt(Name);
 
   // This RNG is guaranteed to produce the same random stream only
   // when the Module ID and thus the input filename is the same. This
@@ -101,7 +102,8 @@ std::unique_ptr<RandomNumberGenerator> Module::createRNG(const Pass* P) const {
   // store salt metadata from the Module constructor.
   Salt += sys::path::filename(getModuleIdentifier());
 
-  return std::unique_ptr<RandomNumberGenerator>(new RandomNumberGenerator(Salt));
+  return std::unique_ptr<RandomNumberGenerator>(
+      new RandomNumberGenerator(Salt));
 }
 
 /// getNamedValue - Return the first global value in the module with

llvm/unittests/IR/ModuleTest.cpp

@@ -63,7 +63,7 @@ TEST(ModuleTest, randomNumberGenerator) {
 
   std::array<int, NBCheck> RandomStreams[2];
   for (auto &RandomStream : RandomStreams) {
-    std::unique_ptr<RandomNumberGenerator> RNG = M.createRNG(&DP);
+    std::unique_ptr<RandomNumberGenerator> RNG = M.createRNG(DP->getPassName());
     std::generate(RandomStream.begin(), RandomStream.end(),
                   [&]() { return dist(*RNG); });
   }