Dmitry Vyukov 2ba80d6df6 tsan: align default value of detect_deadlocks flag with actual behavior
I tricked myself into thinking that deadlock detection is off by default in TSan by looking at the default value of the detect_deadlocks flag and outdated docs. (Created a pull request to update docs.)
I even managed to confuse others: https://groups.google.com/forum/#!topic/thread-sanitizer/xYvnAYwtoDk

However, the default value is overwritten in code (TSan_flags.cc:InitializeFlags). The TSan/deadlock tests also rely on this

This changes aligns the default value of the flag with the actual default behavior.

Author: yln (Julian Lettner)
Reviewed in: https://reviews.llvm.org/D55846

llvm-svn: 349609
2018-12-19 09:34:13 +00:00

36 lines
1.1 KiB
C

// RUN: %clangxx_tsan %s -o %t
// RUN: not %run %t 2>&1 | FileCheck %s
// RUN: %env_tsan_opts=detect_deadlocks=1 not %run %t 2>&1 | FileCheck %s
// RUN: %env_tsan_opts=detect_deadlocks=0 %run %t 2>&1 | FileCheck %s --check-prefix=DISABLED
// RUN: echo "deadlock:main" > %t.supp
// RUN: %env_tsan_opts=suppressions='%t.supp' %run %t 2>&1 | FileCheck %s --check-prefix=DISABLED
// RUN: echo "deadlock:zzzz" > %t.supp
// RUN: %env_tsan_opts=suppressions='%t.supp' not %run %t 2>&1 | FileCheck %s
#include <pthread.h>
#include <stdio.h>
int main() {
pthread_mutex_t mu1, mu2;
pthread_mutex_init(&mu1, NULL);
pthread_mutex_init(&mu2, NULL);
// mu1 => mu2
pthread_mutex_lock(&mu1);
pthread_mutex_lock(&mu2);
pthread_mutex_unlock(&mu2);
pthread_mutex_unlock(&mu1);
// mu2 => mu1
pthread_mutex_lock(&mu2);
pthread_mutex_lock(&mu1);
// CHECK: ThreadSanitizer: lock-order-inversion (potential deadlock)
// DISABLED-NOT: ThreadSanitizer
// DISABLED: PASS
pthread_mutex_unlock(&mu1);
pthread_mutex_unlock(&mu2);
pthread_mutex_destroy(&mu1);
pthread_mutex_destroy(&mu2);
fprintf(stderr, "PASS\n");
}