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b23c5e8c3d
template name is not visible to unqualified lookup. In order to support this without a severe degradation in our ability to diagnose typos in template names, this change significantly restructures the way we handle template-id-shaped syntax for which lookup of the template name finds nothing. Instead of eagerly diagnosing an undeclared template name, we now form a placeholder template-name representing a name that is known to not find any templates. When the parser sees such a name, it attempts to disambiguate whether we have a less-than comparison or a template-id. Any diagnostics or typo-correction for the name are delayed until its point of use. The upshot should be a small improvement of our diagostic quality overall: we now take more syntactic context into account when trying to resolve an undeclared identifier on the left hand side of a '<'. In fact, this works well enough that the backwards-compatible portion (for an undeclared identifier rather than a lookup that finds functions but no function templates) is enabled in all language modes. llvm-svn: 360308
10 lines
518 B
C++
10 lines
518 B
C++
// RUN: %clang_cc1 -fsyntax-only -verify %s
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// <rdar://problem/9173693>
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template< bool C > struct assert { };
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// FIXME: We diagnose the same problem multiple times here because we have no
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// way to indicate in the token stream that we already tried to annotate a
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// template-id and we failed.
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template< bool > struct assert_arg_pred_impl { }; // expected-note 4 {{declared here}}
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template< typename Pred > assert<false> assert_not_arg( void (*)(Pred), typename assert_arg_pred<Pred>::type ); // expected-error 6 {{}}
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