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In PPCReduceCRLogicals after splitting the original MBB into 2, the 2 impacted branches still use original branch probability. This is unreasonable. Suppose we have following code, and the probability of each successor is 50%.
condc = conda || condb
br condc, label %target, label %fallthrough
It can be transformed to following,
br conda, label %target, label %newbb
newbb:
br condb, label %target, label %fallthrough
Since each branch has a probability of 50% to each successor, the total probability to %fallthrough is 25% now, and the total probability to %target is 75%. This actually changed the original profiling data. A more reasonable probability can be set to 70% to the false side for each branch instruction, so the total probability to %fallthrough is close to 50%.
This patch assumes the branch target with two incoming edges have same edge frequency and computes new probability fore each target, and keep the total probability to original targets unchanged.
Differential Revision: https://reviews.llvm.org/D62430
llvm-svn: 362237
249 lines
7.9 KiB
C++
249 lines
7.9 KiB
C++
//===- BranchProbability.h - Branch Probability Wrapper ---------*- C++ -*-===//
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//
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// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
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// See https://llvm.org/LICENSE.txt for license information.
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// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
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//
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//===----------------------------------------------------------------------===//
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//
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// Definition of BranchProbability shared by IR and Machine Instructions.
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//
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//===----------------------------------------------------------------------===//
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#ifndef LLVM_SUPPORT_BRANCHPROBABILITY_H
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#define LLVM_SUPPORT_BRANCHPROBABILITY_H
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#include "llvm/Support/DataTypes.h"
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#include <algorithm>
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#include <cassert>
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#include <climits>
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#include <numeric>
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namespace llvm {
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class raw_ostream;
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// This class represents Branch Probability as a non-negative fraction that is
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// no greater than 1. It uses a fixed-point-like implementation, in which the
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// denominator is always a constant value (here we use 1<<31 for maximum
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// precision).
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class BranchProbability {
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// Numerator
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uint32_t N;
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// Denominator, which is a constant value.
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static const uint32_t D = 1u << 31;
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static const uint32_t UnknownN = UINT32_MAX;
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// Construct a BranchProbability with only numerator assuming the denominator
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// is 1<<31. For internal use only.
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explicit BranchProbability(uint32_t n) : N(n) {}
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public:
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BranchProbability() : N(UnknownN) {}
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BranchProbability(uint32_t Numerator, uint32_t Denominator);
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bool isZero() const { return N == 0; }
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bool isUnknown() const { return N == UnknownN; }
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static BranchProbability getZero() { return BranchProbability(0); }
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static BranchProbability getOne() { return BranchProbability(D); }
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static BranchProbability getUnknown() { return BranchProbability(UnknownN); }
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// Create a BranchProbability object with the given numerator and 1<<31
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// as denominator.
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static BranchProbability getRaw(uint32_t N) { return BranchProbability(N); }
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// Create a BranchProbability object from 64-bit integers.
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static BranchProbability getBranchProbability(uint64_t Numerator,
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uint64_t Denominator);
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// Normalize given probabilties so that the sum of them becomes approximate
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// one.
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template <class ProbabilityIter>
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static void normalizeProbabilities(ProbabilityIter Begin,
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ProbabilityIter End);
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uint32_t getNumerator() const { return N; }
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static uint32_t getDenominator() { return D; }
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// Return (1 - Probability).
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BranchProbability getCompl() const { return BranchProbability(D - N); }
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raw_ostream &print(raw_ostream &OS) const;
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void dump() const;
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/// Scale a large integer.
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///
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/// Scales \c Num. Guarantees full precision. Returns the floor of the
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/// result.
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///
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/// \return \c Num times \c this.
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uint64_t scale(uint64_t Num) const;
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/// Scale a large integer by the inverse.
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///
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/// Scales \c Num by the inverse of \c this. Guarantees full precision.
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/// Returns the floor of the result.
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///
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/// \return \c Num divided by \c this.
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uint64_t scaleByInverse(uint64_t Num) const;
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BranchProbability &operator+=(BranchProbability RHS) {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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// Saturate the result in case of overflow.
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N = (uint64_t(N) + RHS.N > D) ? D : N + RHS.N;
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return *this;
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}
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BranchProbability &operator-=(BranchProbability RHS) {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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// Saturate the result in case of underflow.
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N = N < RHS.N ? 0 : N - RHS.N;
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return *this;
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}
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BranchProbability &operator*=(BranchProbability RHS) {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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N = (static_cast<uint64_t>(N) * RHS.N + D / 2) / D;
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return *this;
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}
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BranchProbability &operator*=(uint32_t RHS) {
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assert(N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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N = (uint64_t(N) * RHS > D) ? D : N * RHS;
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return *this;
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}
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BranchProbability &operator/=(BranchProbability RHS) {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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N = (static_cast<uint64_t>(N) * D + RHS.N / 2) / RHS.N;
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return *this;
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}
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BranchProbability &operator/=(uint32_t RHS) {
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assert(N != UnknownN &&
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"Unknown probability cannot participate in arithmetics.");
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assert(RHS > 0 && "The divider cannot be zero.");
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N /= RHS;
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return *this;
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}
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BranchProbability operator+(BranchProbability RHS) const {
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BranchProbability Prob(*this);
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Prob += RHS;
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return Prob;
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}
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BranchProbability operator-(BranchProbability RHS) const {
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BranchProbability Prob(*this);
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Prob -= RHS;
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return Prob;
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}
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BranchProbability operator*(BranchProbability RHS) const {
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BranchProbability Prob(*this);
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Prob *= RHS;
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return Prob;
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}
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BranchProbability operator*(uint32_t RHS) const {
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BranchProbability Prob(*this);
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Prob *= RHS;
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return Prob;
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}
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BranchProbability operator/(BranchProbability RHS) const {
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BranchProbability Prob(*this);
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Prob /= RHS;
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return Prob;
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}
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BranchProbability operator/(uint32_t RHS) const {
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BranchProbability Prob(*this);
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Prob /= RHS;
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return Prob;
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}
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bool operator==(BranchProbability RHS) const { return N == RHS.N; }
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bool operator!=(BranchProbability RHS) const { return !(*this == RHS); }
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bool operator<(BranchProbability RHS) const {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in comparisons.");
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return N < RHS.N;
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}
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bool operator>(BranchProbability RHS) const {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in comparisons.");
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return RHS < *this;
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}
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bool operator<=(BranchProbability RHS) const {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in comparisons.");
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return !(RHS < *this);
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}
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bool operator>=(BranchProbability RHS) const {
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assert(N != UnknownN && RHS.N != UnknownN &&
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"Unknown probability cannot participate in comparisons.");
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return !(*this < RHS);
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}
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};
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inline raw_ostream &operator<<(raw_ostream &OS, BranchProbability Prob) {
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return Prob.print(OS);
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}
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template <class ProbabilityIter>
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void BranchProbability::normalizeProbabilities(ProbabilityIter Begin,
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ProbabilityIter End) {
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if (Begin == End)
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return;
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unsigned UnknownProbCount = 0;
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uint64_t Sum = std::accumulate(Begin, End, uint64_t(0),
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[&](uint64_t S, const BranchProbability &BP) {
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if (!BP.isUnknown())
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return S + BP.N;
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UnknownProbCount++;
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return S;
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});
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if (UnknownProbCount > 0) {
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BranchProbability ProbForUnknown = BranchProbability::getZero();
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// If the sum of all known probabilities is less than one, evenly distribute
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// the complement of sum to unknown probabilities. Otherwise, set unknown
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// probabilities to zeros and continue to normalize known probabilities.
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if (Sum < BranchProbability::getDenominator())
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ProbForUnknown = BranchProbability::getRaw(
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(BranchProbability::getDenominator() - Sum) / UnknownProbCount);
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std::replace_if(Begin, End,
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[](const BranchProbability &BP) { return BP.isUnknown(); },
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ProbForUnknown);
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if (Sum <= BranchProbability::getDenominator())
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return;
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}
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if (Sum == 0) {
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BranchProbability BP(1, std::distance(Begin, End));
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std::fill(Begin, End, BP);
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return;
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}
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for (auto I = Begin; I != End; ++I)
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I->N = (I->N * uint64_t(D) + Sum / 2) / Sum;
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}
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}
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#endif
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