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Separate the type-became-concrete case from the type-is-resolved case, the

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former of which takes much less work than the later.  This speeds up linking
eon from 3.749 to 3.637s with a release build (about 3%).


git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@24338 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chris Lattner 2005-11-13 01:27:50 +00:00
parent ea2fdf9380
commit 66cafb33bc
1 changed files with 31 additions and 21 deletions
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44
lib/VMCore/Type.cpp
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@ -736,14 +736,34 @@ public:
/// The specified iterator tells us what the type USED to look like.
void finishRefinement(TypeClass *Ty, const DerivedType *OldType,
const Type *NewType) {
// Either NewTy == OldTy (in which case the specified type just became
// concrete) or they are different an the Ty is thought to be abstract.
assert((Ty->isAbstract() || OldType == NewType) &&
"Refining a non-abstract type!");
#ifdef DEBUG_MERGE_TYPES
std::cerr << "refineAbstractTy(" << (void*)OldType << "[" << *OldType
<< "], " << (void*)NewType << " [" << *NewType << "])\n";
#endif
// If NewTy == OldTy, then the type just became concrete. In this case, we
// don't need to change the current type, we just need to drop uses of the
// type and potentially mark Ty as concrete now too.
if (OldType == NewType) {
// If the element just became concrete, remove 'ty' from the abstract
// type user list for the type. Do this for as many times as Ty uses
// OldType.
for (unsigned i = 0, e = Ty->ContainedTys.size(); i != e; ++i)
if (Ty->ContainedTys[i] == OldType)
OldType->removeAbstractTypeUser(Ty);
// If the type is currently thought to be abstract, rescan all of our
// subtypes to see if the type has just become concrete! Note that this
// may send out notifications to AbstractTypeUsers that types become
// concrete.
if (Ty->isAbstract())
Ty->PromoteAbstractToConcrete();
return;
}
// Otherwise, we are changing one subelement type into another. Clearly the
// OldType must have been abstract, making us abstract.
assert(Ty->isAbstract() && "Refining a non-abstract type!");
// Make a temporary type holder for the type so that it doesn't disappear on
// us when we erase the entry from the map.
@ -759,31 +779,23 @@ public:
unsigned OldTypeHash = ValType::hashTypeStructure(Ty);
// Find the type element we are refining... and change it now!
if (!OldType->isAbstract()) {
// If the element just became concrete, remove 'ty' from the abstract
// type user list for the type.
for (unsigned i = 0, e = Ty->ContainedTys.size(); i != e; ++i)
if (Ty->ContainedTys[i] == OldType)
OldType->removeAbstractTypeUser(Ty);
} else {
assert(OldType != NewType && "Unknown case!");
for (unsigned i = 0, e = Ty->ContainedTys.size(); i != e; ++i)
if (Ty->ContainedTys[i] == OldType)
Ty->ContainedTys[i] = NewType;
}
unsigned NewTypeHash = ValType::hashTypeStructure(Ty);
// If there are no cycles going through this node, we can do a simple,
// efficient lookup in the map, instead of an inefficient nasty linear
// lookup.
if (!Ty->isAbstract() || !TypeHasCycleThroughItself(Ty)) {
if (!TypeHasCycleThroughItself(Ty)) {
typename std::map<ValType, PATypeHolder>::iterator I;
bool Inserted;
tie(I, Inserted) = Map.insert(std::make_pair(ValType::get(Ty), Ty));
if (!Inserted) {
assert(OldType != NewType);
// Refined to a different type altogether?
RemoveFromTypesByHash(NewTypeHash, Ty);
RemoveFromTypesByHash(OldTypeHash, Ty);
// We already have this type in the table. Get rid of the newly refined
// type.
@ -792,8 +804,6 @@ public:
return;
}
} else {
assert(Ty->isAbstract() && "Potentially replacing a non-abstract type?");
// Now we check to see if there is an existing entry in the table which is
// structurally identical to the newly refined type. If so, this type
// gets refined to the pre-existing type.