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[APInt] Fix extractBits to correctly handle Result.isSingleWord() case.
Summary: extractBits assumes that `!this->isSingleWord() implies !Result.isSingleWord()`, which may not necessarily be true. Handle both cases. Reviewers: RKSimon Subscribers: sanjoy, llvm-commits, hiraditya Differential Revision: https://reviews.llvm.org/D43363 git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@325311 91177308-0d34-0410-b5e6-96231b3b80d8
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@@ -428,11 +428,12 @@ APInt APInt::extractBits(unsigned numBits, unsigned bitPosition) const {
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unsigned NumSrcWords = getNumWords();
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unsigned NumDstWords = Result.getNumWords();
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uint64_t *DestPtr = Result.isSingleWord() ? &Result.U.VAL : Result.U.pVal;
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for (unsigned word = 0; word < NumDstWords; ++word) {
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uint64_t w0 = U.pVal[loWord + word];
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uint64_t w1 =
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(loWord + word + 1) < NumSrcWords ? U.pVal[loWord + word + 1] : 0;
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Result.U.pVal[word] = (w0 >> loBit) | (w1 << (APINT_BITS_PER_WORD - loBit));
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DestPtr[word] = (w0 >> loBit) | (w1 << (APINT_BITS_PER_WORD - loBit));
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}
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return Result.clearUnusedBits();
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