[LCG] Re-implement the basic isParentOf, isAncestorOf, isChildOf, and

isDescendantOf methods on RefSCCs in terms of the forward edges rather
than the parent sets.

This is technically slower, but probably not interestingly slower, and
all of these routines were already so expensive that they're guarded
behind both !NDEBUG and EXPENSIVE_CHECKS.

This removes another non-critical usage of parent sets.

I've also added some comments to try and help clarify to any potential
users the costs of these routines. They're mostly useful for debugging,
asserts, or other queries.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@310170 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chandler Carruth 2017-08-05 06:24:09 +00:00
parent 95f263eb86
commit 8d16ccbe0f
2 changed files with 61 additions and 20 deletions

View File

@ -631,20 +631,34 @@ public:
return make_range(parent_begin(), parent_end());
}
/// Test if this RefSCC is a parent of \a C.
bool isParentOf(const RefSCC &C) const { return C.isChildOf(*this); }
/// Test if this RefSCC is a parent of \a RC.
///
/// CAUTION: This method walks every edge in the \c RefSCC, it can be very
/// expensive.
bool isParentOf(const RefSCC &RC) const;
/// Test if this RefSCC is an ancestor of \a C.
bool isAncestorOf(const RefSCC &C) const { return C.isDescendantOf(*this); }
/// Test if this RefSCC is an ancestor of \a RC.
///
/// CAUTION: This method walks the directed graph of edges as far as
/// necessary to find a possible path to the argument. In the worst case
/// this may walk the entire graph and can be extremely expensive.
bool isAncestorOf(const RefSCC &RC) const;
/// Test if this RefSCC is a child of \a C.
bool isChildOf(const RefSCC &C) const {
return Parents.count(const_cast<RefSCC *>(&C));
/// Test if this RefSCC is a child of \a RC.
///
/// CAUTION: This method walks every edge in the argument \c RefSCC, it can
/// be very expensive.
bool isChildOf(const RefSCC &RC) const { return RC.isParentOf(*this); }
/// Test if this RefSCC is a descendant of \a RC.
///
/// CAUTION: This method walks the directed graph of edges as far as
/// necessary to find a possible path from the argument. In the worst case
/// this may walk the entire graph and can be extremely expensive.
bool isDescendantOf(const RefSCC &RC) const {
return RC.isAncestorOf(*this);
}
/// Test if this RefSCC is a descendant of \a C.
bool isDescendantOf(const RefSCC &C) const;
/// Provide a short name by printing this RefSCC to a std::string.
///
/// This copes with the fact that we don't have a name per-se for an RefSCC

View File

@ -334,17 +334,44 @@ void LazyCallGraph::RefSCC::verify() {
}
#endif
bool LazyCallGraph::RefSCC::isDescendantOf(const RefSCC &C) const {
// Walk up the parents of this SCC and verify that we eventually find C.
SmallVector<const RefSCC *, 4> AncestorWorklist;
AncestorWorklist.push_back(this);
bool LazyCallGraph::RefSCC::isParentOf(const RefSCC &RC) const {
if (&RC == this)
return false;
// Search all edges to see if this is a parent.
for (SCC &C : *this)
for (Node &N : C)
for (Edge &E : *N)
if (G->lookupRefSCC(E.getNode()) == &RC)
return true;
return false;
}
bool LazyCallGraph::RefSCC::isAncestorOf(const RefSCC &RC) const {
if (&RC == this)
return false;
// For each descendant of this RefSCC, see if one of its children is the
// argument. If not, add that descendant to the worklist and continue
// searching.
SmallVector<const RefSCC *, 4> Worklist;
SmallPtrSet<const RefSCC *, 4> Visited;
Worklist.push_back(this);
Visited.insert(this);
do {
const RefSCC *AncestorC = AncestorWorklist.pop_back_val();
if (AncestorC->isChildOf(C))
return true;
for (const RefSCC *ParentC : AncestorC->Parents)
AncestorWorklist.push_back(ParentC);
} while (!AncestorWorklist.empty());
const RefSCC &DescendantRC = *Worklist.pop_back_val();
for (SCC &C : DescendantRC)
for (Node &N : C)
for (Edge &E : *N) {
auto *ChildRC = G->lookupRefSCC(E.getNode());
if (ChildRC == &RC)
return true;
if (!ChildRC || !Visited.insert(ChildRC).second)
continue;
Worklist.push_back(ChildRC);
}
} while (!Worklist.empty());
return false;
}