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Third try at fixing this. ;] Go back to using std::remove_if, which has
most of the behavior we want, but wrap the predicate in one which erases elements from the set if they pass the predicate. Oh what I wouldn't give for a lambda here. Let me know if the predicate wrapping is too much magic. ;] git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@165076 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -141,15 +141,12 @@ public:
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/// \returns true if any element is removed.
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template <typename UnaryPredicate>
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bool remove_if(UnaryPredicate P) {
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typename vector_type::iterator B = std::partition(vector_.begin(),
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vector_.end(),
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std::not1(P)),
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E = vector_.end();
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if (B == E)
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typename vector_type::iterator I
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= std::remove_if(vector_.begin(), vector_.end(),
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TestAndEraseFromSet<UnaryPredicate>(P, set_));
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if (I == vector_.end())
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return false;
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for (typename vector_type::iterator I = B; I != E; ++I)
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set_.erase(*I);
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vector_.erase(B, E);
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vector_.erase(I, vector_.end());
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return true;
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}
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@ -188,6 +185,29 @@ public:
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}
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private:
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/// \brief A wrapper predicate designed for use with std::remove_if.
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///
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/// This predicate wraps a predicate suitable for use with std::remove_if to
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/// call set_.erase(x) on each element which is slated for removal.
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template <typename UnaryPredicate>
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class TestAndEraseFromSet {
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UnaryPredicate P;
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set_type &set_;
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public:
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typedef typename UnaryPredicate::argument_type argument_type;
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TestAndEraseFromSet(UnaryPredicate P, set_type &set_) : P(P), set_(set_) {}
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bool operator()(argument_type Arg) {
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if (P(Arg)) {
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set_.erase(Arg);
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return true;
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}
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return false;
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}
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};
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set_type set_; ///< The set.
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vector_type vector_; ///< The vector.
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};
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