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6edb7e8c20
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@21494 91177308-0d34-0410-b5e6-96231b3b80d8
149 lines
2.9 KiB
LLVM
149 lines
2.9 KiB
LLVM
; This test makes sure that these instructions are properly eliminated.
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;
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; RUN: llvm-as < %s | opt -instcombine | llvm-dis | not grep 'xor '
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%G1 = global uint 0
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%G2 = global uint 0
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implementation
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bool %test0(bool %A) {
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%B = xor bool %A, false
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ret bool %B
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}
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int %test1(int %A) {
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%B = xor int %A, 0
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ret int %B
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}
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bool %test2(bool %A) {
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%B = xor bool %A, %A
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ret bool %B
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}
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int %test3(int %A) {
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%B = xor int %A, %A
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ret int %B
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}
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int %test4(int %A) { ; A ^ ~A == -1
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%NotA = xor int -1, %A
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%B = xor int %A, %NotA
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ret int %B
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}
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uint %test5(uint %A) { ; (A|B)^B == A & (~B)
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%t1 = or uint %A, 123
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%r = xor uint %t1, 123
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ret uint %r
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}
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ubyte %test6(ubyte %A) {
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%B = xor ubyte %A, 17
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%C = xor ubyte %B, 17
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ret ubyte %C
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}
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; (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
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int %test7(int %A, int %B) {
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%A1 = and int %A, 7
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%B1 = and int %B, 128
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%C1 = xor int %A1, %B1
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ret int %C1
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}
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ubyte %test8(bool %c) {
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%d = xor bool %c, true ; invert the condition
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br bool %d, label %True, label %False
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True:
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ret ubyte 1
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False:
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ret ubyte 3
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}
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bool %test9(ubyte %A) {
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%B = xor ubyte %A, 123 ; xor can be eliminated
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%C = seteq ubyte %B, 34
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ret bool %C
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}
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ubyte %test10(ubyte %A) {
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%B = and ubyte %A, 3
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%C = xor ubyte %B, 4 ; transform into an OR
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ret ubyte %C
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}
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ubyte %test11(ubyte %A) {
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%B = or ubyte %A, 12
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%C = xor ubyte %B, 4 ; transform into an AND
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ret ubyte %C
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}
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bool %test12(ubyte %A) {
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%B = xor ubyte %A, 4
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%c = setne ubyte %B, 0
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ret bool %c
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}
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bool %test13(ubyte %A, ubyte %B) {
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%C = setlt ubyte %A, %B
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%D = setgt ubyte %A, %B
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%E = xor bool %C, %D ; E = setne %A, %B
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ret bool %E
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}
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bool %test14(ubyte %A, ubyte %B) {
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%C = seteq ubyte %A, %B
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%D = setne ubyte %B, %A
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%E = xor bool %C, %D ; E = true
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ret bool %E
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}
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uint %test15(uint %A) { ; ~(X-1) == -X
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%B = add uint %A, 4294967295
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%C = xor uint %B, 4294967295
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ret uint %C
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}
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uint %test16(uint %A) { ; ~(X+c) == (-c-1)-X
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%B = add uint %A, 123 ; A generalization of the previous case
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%C = xor uint %B, 4294967295
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ret uint %C
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}
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uint %test17(uint %A) { ; ~(c-X) == X-(c-1) == X+(-c+1)
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%B = sub uint 123, %A
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%C = xor uint %B, 4294967295
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ret uint %C
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}
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uint %test18(uint %A) { ; C - ~X == X + (1+C)
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%B = xor uint %A, 4294967295; -~X == 0 - ~X == X+1
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%C = sub uint 123, %B
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ret uint %C
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}
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uint %test19(uint %A, uint %B) {
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%C = xor uint %A, %B
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%D = xor uint %C, %A ; A terms cancel, D = B
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ret uint %D
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}
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void %test20(uint %A, uint %B) { ; The "swap idiom"
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%tmp.2 = xor uint %B, %A
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%tmp.5 = xor uint %tmp.2, %B
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%tmp.8 = xor uint %tmp.5, %tmp.2
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store uint %tmp.8, uint* %G1 ; tmp.8 = B
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store uint %tmp.5, uint* %G2 ; tmp.5 = A
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ret void
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}
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int %test21(bool %C, int %A, int %B) {
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%C2 = xor bool %C, true
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%D = select bool %C2, int %A, int %B
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ret int %D
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}
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