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Get rid of the printout from the low-level system interface

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git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@15161 91177308-0d34-0410-b5e6-96231b3b80d8
This commit is contained in:
Chris Lattner 2004-07-24 07:50:48 +00:00
parent e96b2ed211
commit 21ddf17ff6
1 changed files with 13 additions and 24 deletions
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37
lib/Support/SystemUtils.cpp
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@ -182,34 +182,23 @@ int llvm::RunProgramWithTimeout(const std::string &ProgramPath,
alarm(NumSeconds);
int Status;
while (wait(&Status) != Child) {
while (wait(&Status) != Child)
if (errno == EINTR) {
if (Timeout) {
static bool FirstTimeout = true;
if (FirstTimeout) {
std::cout <<
"*** Program execution timed out! This mechanism is designed to handle\n"
" programs stuck in infinite loops gracefully. The -timeout option\n"
" can be used to change the timeout threshold or disable it completely\n"
" (with -timeout=0). This message is only displayed once.\n";
FirstTimeout = false;
}
// Kill the child.
kill(Child, SIGKILL);
if (wait(&Status) != Child)
std::cerr << "Something funny happened waiting for the child!\n";
alarm(0);
sigaction(SIGALRM, &Old, 0);
return -1; // Timeout detected
} else {
std::cerr << "Error waiting for child process!\n";
exit(1);
}
// Kill the child.
kill(Child, SIGKILL);
if (wait(&Status) != Child)
std::cerr << "Something funny happened waiting for the child!\n";
alarm(0);
sigaction(SIGALRM, &Old, 0);
return -1; // Timeout detected
} else {
std::cerr << "Error waiting for child process!\n";
exit(1);
}
}
alarm(0);
sigaction(SIGALRM, &Old, 0);