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[ConstantRange][SimplifyCFG] Add a helper method to allow SimplifyCFG to determine if a ConstantRange has more than 8 elements without requiring an allocation if the ConstantRange is 64-bits wide.
Previously SimplifyCFG used getSetSize which returns an APInt that is 1 bit wider than the ConstantRange's bit width. In the reasonably common case that the ConstantRange is 64-bits wide, this requires returning a 65-bit APInt. APInt's can only store 64-bits without a memory allocation so this is inefficient. The new method takes the 8 as an input and tells if the range contains more than that many elements without requiring any wider math. git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@302385 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -169,6 +169,9 @@ public:
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/// Compare set size of this range with the range CR.
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bool isSizeStrictlySmallerThan(const ConstantRange &CR) const;
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// Compare set size of this range with Value.
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bool isSizeLargerThan(uint64_t MaxSize) const;
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/// Return the largest unsigned value contained in the ConstantRange.
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APInt getUnsignedMax() const;
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@ -260,6 +260,17 @@ ConstantRange::isSizeStrictlySmallerThan(const ConstantRange &Other) const {
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return (Upper - Lower).ult(Other.Upper - Other.Lower);
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}
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bool
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ConstantRange::isSizeLargerThan(uint64_t MaxSize) const {
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assert(MaxSize && "MaxSize can't be 0.");
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// If this a full set, we need special handling to avoid needing an extra bit
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// to represent the size.
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if (isFullSet())
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return APInt::getMaxValue(getBitWidth()).ugt(MaxSize - 1);
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return (Upper - Lower).ugt(MaxSize);
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}
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APInt ConstantRange::getUnsignedMax() const {
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if (isFullSet() || isWrappedSet())
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return APInt::getMaxValue(getBitWidth());
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@ -596,7 +596,7 @@ private:
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Span = Span.inverse();
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// If there are a ton of values, we don't want to make a ginormous switch.
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if (Span.getSetSize().ugt(8) || Span.isEmptySet()) {
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if (Span.isSizeLargerThan(8) || Span.isEmptySet()) {
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return false;
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}
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