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x86 uses 5 operands for most memory refs now.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@83733 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -1812,24 +1812,27 @@ define fastcc i32 @tailcaller(i32 %in1, i32 %in2) {
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<div class="doc_code">
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<pre>
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Base + [1,2,4,8] * IndexReg + Disp32
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SegmentReg: Base + [1,2,4,8] * IndexReg + Disp32
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</pre>
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</div>
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<p>In order to represent this, LLVM tracks no less than 4 operands for each
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<p>In order to represent this, LLVM tracks no less than 5 operands for each
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memory operand of this form. This means that the "load" form of
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'<tt>mov</tt>' has the following <tt>MachineOperand</tt>s in this order:</p>
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<div class="doc_code">
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<pre>
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Index: 0 | 1 2 3 4
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Meaning: DestReg, | BaseReg, Scale, IndexReg, Displacement
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OperandTy: VirtReg, | VirtReg, UnsImm, VirtReg, SignExtImm
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Index: 0 | 1 2 3 4 5
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Meaning: DestReg, | BaseReg, Scale, IndexReg, Displacement Segment
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OperandTy: VirtReg, | VirtReg, UnsImm, VirtReg, SignExtImm PhysReg
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</pre>
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</div>
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<p>Stores, and all other instructions, treat the four memory operands in the
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same way and in the same order.</p>
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same way and in the same order. If the segment register is unspecified
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(regno = 0), then no segment override is generated. "Lea" operations do not
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have a segment register specified, so they only have 4 operands for their
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memory reference.</p>
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</div>
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