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[SimplifyCFG] eliminate switch cases based on known range of switch condition
This was noted in PR24766: https://llvm.org/bugs/show_bug.cgi?id=24766#c2 We may not know whether the sign bit(s) are zero or one, but we can still optimize based on knowing that the sign bit is repeated. Differential Revision: http://reviews.llvm.org/D20275 git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@270222 91177308-0d34-0410-b5e6-96231b3b80d8
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@ -3914,14 +3914,20 @@ static bool EliminateDeadSwitchCases(SwitchInst *SI, AssumptionCache *AC,
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APInt KnownZero(Bits, 0), KnownOne(Bits, 0);
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computeKnownBits(Cond, KnownZero, KnownOne, DL, 0, AC, SI);
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// We can also eliminate cases by determining that their values are outside of
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// the limited range of the condition based on how many significant (non-sign)
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// bits are in the condition value.
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unsigned ExtraSignBits = ComputeNumSignBits(Cond, DL, 0, AC, SI) - 1;
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unsigned MaxSignificantBitsInCond = Bits - ExtraSignBits;
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// Gather dead cases.
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SmallVector<ConstantInt *, 8> DeadCases;
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for (auto &Case : SI->cases()) {
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if ((Case.getCaseValue()->getValue() & KnownZero) != 0 ||
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(Case.getCaseValue()->getValue() & KnownOne) != KnownOne) {
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APInt CaseVal = Case.getCaseValue()->getValue();
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if ((CaseVal & KnownZero) != 0 || (CaseVal & KnownOne) != KnownOne ||
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(CaseVal.getMinSignedBits() > MaxSignificantBitsInCond)) {
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DeadCases.push_back(Case.getCaseValue());
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DEBUG(dbgs() << "SimplifyCFG: switch case '" << Case.getCaseValue()
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<< "' is dead.\n");
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DEBUG(dbgs() << "SimplifyCFG: switch case " << CaseVal << " is dead.\n");
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}
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}
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@ -49,14 +49,10 @@ c:
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define i1 @repeated_signbits(i8 %condition) {
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; CHECK-LABEL: @repeated_signbits(
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; CHECK: switch i32
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; CHECK-DAG: i32 -2147483648, label %a
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; CHECK-DAG: i32 -129, label %a
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; CHECK-DAG: i32 -128, label %a
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; CHECK-DAG: i32 -1, label %a
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; CHECK-DAG: i32 0, label %a
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; CHECK-DAG: i32 127, label %a
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; CHECK-DAG: i32 128, label %a
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; CHECK-DAG: i32 2147483647, label %a
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; CHECK-NEXT: ]
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;
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entry:
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