llvm/lib/Analysis/Interval.cpp
Chris Lattner 1ff1ff70e3 Fixes for PR341
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@14843 91177308-0d34-0410-b5e6-96231b3b80d8
2004-07-15 02:31:46 +00:00

58 lines
2.0 KiB
C++

//===- Interval.cpp - Interval class code ---------------------------------===//
//
// The LLVM Compiler Infrastructure
//
// This file was developed by the LLVM research group and is distributed under
// the University of Illinois Open Source License. See LICENSE.TXT for details.
//
//===----------------------------------------------------------------------===//
//
// This file contains the definition of the Interval class, which represents a
// partition of a control flow graph of some kind.
//
//===----------------------------------------------------------------------===//
#include "llvm/Analysis/Interval.h"
#include "llvm/BasicBlock.h"
#include "llvm/Support/CFG.h"
#include <algorithm>
using namespace llvm;
//===----------------------------------------------------------------------===//
// Interval Implementation
//===----------------------------------------------------------------------===//
// isLoop - Find out if there is a back edge in this interval...
//
bool Interval::isLoop() const {
// There is a loop in this interval iff one of the predecessors of the header
// node lives in the interval.
for (::pred_iterator I = ::pred_begin(HeaderNode), E = ::pred_end(HeaderNode);
I != E; ++I) {
if (contains(*I)) return true;
}
return false;
}
void Interval::print(std::ostream &o) const {
o << "-------------------------------------------------------------\n"
<< "Interval Contents:\n";
// Print out all of the basic blocks in the interval...
for (std::vector<BasicBlock*>::const_iterator I = Nodes.begin(),
E = Nodes.end(); I != E; ++I)
o << **I << "\n";
o << "Interval Predecessors:\n";
for (std::vector<BasicBlock*>::const_iterator I = Predecessors.begin(),
E = Predecessors.end(); I != E; ++I)
o << **I << "\n";
o << "Interval Successors:\n";
for (std::vector<BasicBlock*>::const_iterator I = Successors.begin(),
E = Successors.end(); I != E; ++I)
o << **I << "\n";
}