darling-libxml2/example/gjobread.c
1999-06-13 14:37:07 +00:00

247 lines
5.8 KiB
C

/*
* gjobread.c : a small test program for gnome jobs XML format
*
* See Copyright for the status of this software.
*
* Daniel.Veillard@w3.org
*/
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include "parser.h"
#define DEBUG(x) printf(x)
/*
* A person record
*/
typedef struct person {
char *name;
char *email;
char *company;
char *organisation;
char *smail;
char *webPage;
char *phone;
} person, *personPtr;
/*
* And the code needed to parse it
*/
personPtr parsePerson(xmlDocPtr doc, xmlNsPtr ns, xmlNodePtr cur) {
personPtr ret = NULL;
DEBUG("parsePerson\n");
/*
* allocate the struct
*/
ret = (personPtr) malloc(sizeof(person));
if (ret == NULL) {
fprintf(stderr,"out of memory\n");
return(NULL);
}
memset(ret, 0, sizeof(person));
/* We don't care what the top level element name is */
cur = cur->childs;
while (cur != NULL) {
if ((!strcmp(cur->name, "Person")) && (cur->ns == ns))
ret->name = xmlNodeListGetString(doc, cur->childs, 1);
if ((!strcmp(cur->name, "Email")) && (cur->ns == ns))
ret->email = xmlNodeListGetString(doc, cur->childs, 1);
cur = cur->next;
}
return(ret);
}
/*
* and to print it
*/
void printPerson(personPtr cur) {
if (cur == NULL) return;
printf("------ Person\n");
if (cur->name) printf(" name: %s\n", cur->name);
if (cur->email) printf(" email: %s\n", cur->email);
if (cur->company) printf(" company: %s\n", cur->company);
if (cur->organisation) printf(" organisation: %s\n", cur->organisation);
if (cur->smail) printf(" smail: %s\n", cur->smail);
if (cur->webPage) printf(" Web: %s\n", cur->webPage);
if (cur->phone) printf(" phone: %s\n", cur->phone);
printf("------\n");
}
/*
* a Description for a Job
*/
typedef struct job {
char *projectID;
char *application;
char *category;
personPtr contact;
int nbDevelopers;
personPtr developers[100]; /* using dynamic alloc is left as an exercise */
} job, *jobPtr;
/*
* And the code needed to parse it
*/
jobPtr parseJob(xmlDocPtr doc, xmlNsPtr ns, xmlNodePtr cur) {
jobPtr ret = NULL;
DEBUG("parseJob\n");
/*
* allocate the struct
*/
ret = (jobPtr) malloc(sizeof(job));
if (ret == NULL) {
fprintf(stderr,"out of memory\n");
return(NULL);
}
memset(ret, 0, sizeof(job));
/* We don't care what the top level element name is */
cur = cur->childs;
while (cur != NULL) {
if ((!strcmp(cur->name, "Project")) && (cur->ns == ns)) {
ret->projectID = xmlGetProp(cur, "ID");
if (ret->projectID == NULL) {
fprintf(stderr, "Project has no ID\n");
}
}
if ((!strcmp(cur->name, "Application")) && (cur->ns == ns))
ret->application = xmlNodeListGetString(doc, cur->childs, 1);
if ((!strcmp(cur->name, "Category")) && (cur->ns == ns))
ret->category = xmlNodeListGetString(doc, cur->childs, 1);
if ((!strcmp(cur->name, "Contact")) && (cur->ns == ns))
ret->contact = parsePerson(doc, ns, cur);
cur = cur->next;
}
return(ret);
}
/*
* and to print it
*/
void printJob(jobPtr cur) {
int i;
if (cur == NULL) return;
printf("======= Job\n");
if (cur->projectID != NULL) printf("projectID: %s\n", cur->projectID);
if (cur->application != NULL) printf("application: %s\n", cur->application);
if (cur->category != NULL) printf("category: %s\n", cur->category);
if (cur->contact != NULL) printPerson(cur->contact);
printf("%d developers\n", cur->nbDevelopers);
for (i = 0;i < cur->nbDevelopers;i++) printPerson(cur->developers[i]);
printf("======= \n");
}
/*
* A pool of Gnome Jobs
*/
typedef struct gjob {
int nbJobs;
jobPtr jobs[500]; /* using dynamic alloc is left as an exercise */
} gJob, *gJobPtr;
gJobPtr parseGjobFile(char *filename) {
xmlDocPtr doc;
gJobPtr ret;
jobPtr job;
xmlNsPtr ns;
xmlNodePtr cur;
/*
* build an XML tree from a the file;
*/
doc = xmlParseFile(filename);
if (doc == NULL) return(NULL);
/*
* Check the document is of the right kind
*/
cur = doc->root;
if (cur == NULL) {
fprintf(stderr,"empty document\n");
xmlFreeDoc(doc);
return(NULL);
}
ns = xmlSearchNsByHref(doc, cur, "http://www.gnome.org/some-location");
if (ns == NULL) {
fprintf(stderr,
"document of the wrong type, GJob Namespace not found\n");
xmlFreeDoc(doc);
return(NULL);
}
if (strcmp(cur->name, "Helping")) {
fprintf(stderr,"document of the wrong type, root node != Helping");
xmlFreeDoc(doc);
return(NULL);
}
/*
* Allocate the structure to be returned.
*/
ret = (gJobPtr) malloc(sizeof(gJob));
if (ret == NULL) {
fprintf(stderr,"out of memory\n");
xmlFreeDoc(doc);
return(NULL);
}
memset(ret, 0, sizeof(gJob));
/*
* Now, walk the tree.
*/
/* First level we expect just Jobs */
cur = cur->childs;
if ((strcmp(cur->name, "Jobs")) || (cur->ns != ns)) {
fprintf(stderr,"document of the wrong type, Jobs expected");
xmlFreeDoc(doc);
free(ret);
return(NULL);
}
/* Second level is a list of Job, but be laxist */
cur = cur->childs;
while (cur != NULL) {
if ((!strcmp(cur->name, "Job")) && (cur->ns == ns)) {
job = parseJob(doc, ns, cur);
if (job != NULL)
ret->jobs[ret->nbJobs++] = job;
if (ret->nbJobs >= 500) break;
}
cur = cur->next;
}
return(ret);
}
void handleGjob(gJobPtr cur) {
int i;
/*
* Do whatever you want and free the structure.
*/
printf("%d Jobs registered\n", cur->nbJobs);
for (i = 0; i < cur->nbJobs; i++) printJob(cur->jobs[i]);
}
int main(int argc, char **argv) {
int i;
gJobPtr cur;
for (i = 1; i < argc ; i++) {
cur = parseGjobFile(argv[i]);
handleGjob(cur);
}
return(0);
}