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How do I run a single node when it's already added to a graph? #153

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opened 2026-02-15 17:16:24 -05:00 by yindo · 4 comments
yindo commented 2026-02-15 17:16:24 -05:00
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Originally created by @oneWalker on GitHub (Dec 25, 2024).

The question is the title, how to trigger a single Node?

Originally created by @oneWalker on GitHub (Dec 25, 2024). The question is the title, how to trigger a single Node?
yindo closed this issue 2026-02-15 17:16:24 -05:00
yindo commented 2026-02-15 17:16:25 -05:00
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@guidorietbroek commented on GitHub (Dec 25, 2024):

This section is for issues.

You should run nodes depending on the edges. Beginnen with START and ending with END.

@guidorietbroek commented on GitHub (Dec 25, 2024): This section is for issues. You should run nodes depending on the edges. Beginnen with START and ending with END.
yindo commented 2026-02-15 17:16:25 -05:00
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@oneWalker commented on GitHub (Dec 26, 2024):

This section is for issues.

You should run nodes depending on the edges. Beginnen with START and ending with END.

single node is not the whole graph. There are two concepts.

Its the whole graph that beignning with STAT and endging with END, not single node.

@oneWalker commented on GitHub (Dec 26, 2024): > This section is for issues. > > You should run nodes depending on the edges. Beginnen with START and ending with END. single node is not the whole graph. There are two concepts. Its the whole graph that beignning with STAT and endging with END, not single node.
yindo commented 2026-02-15 17:16:25 -05:00
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@jacoblee93 commented on GitHub (Dec 30, 2024):

You can do:

await graph.nodes[nodeName].invoke({});

This is not yet documented, will close the issue when it is!

@jacoblee93 commented on GitHub (Dec 30, 2024): You can do: ```ts await graph.nodes[nodeName].invoke({}); ``` This is not yet documented, will close the issue when it is!
yindo commented 2026-02-15 17:16:26 -05:00
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@oneWalker commented on GitHub (Dec 30, 2024):

You can do:

await graph.nodes[nodeName].invoke({});

This is not yet documented, will close the issue when it is!

It works, and thanks a lot for making my codes more clean.
I really appreciate your work on the great library.

@oneWalker commented on GitHub (Dec 30, 2024): > You can do: > > ```ts > await graph.nodes[nodeName].invoke({}); > ``` > > This is not yet documented, will close the issue when it is! It works, and thanks a lot for making my codes more clean. I really appreciate your work on the great library.
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Reference: langchain-ai/langgraphjs#153
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