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Correctly handle DEBUG build with cmake.

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1) release was not actually selected at configuration time
2) DEBUG=1 would cause an error

Now it works for single and multi config generators.

https://github.com/libretro/libretro-super/issues/1970

Signed-off-by: Andrea Odetti <[email protected]>
This commit is contained in:
Andrea Odetti
2026-08-29 09:00:00 +01:00
parent e720b23681
commit 722dff032d
1 changed files with 9 additions and 4 deletions
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libretro-build-common.sh
+9 -4
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@@ -260,14 +260,19 @@ build_cmake() {
$core_build_configure $core_build_configure
if [ -n "$DEBUG" ]; then
cmake_build_type="Debug"
else
cmake_build_type="Release"
fi
if [ -z "$NOCLEAN" ]; then if [ -z "$NOCLEAN" ]; then
$core_build_preclean $core_build_preclean
echo_cmd "$make_cmdline --build build --target clean" echo_cmd "$make_cmdline --build build --target clean"
fi fi
make_cmdline1="$make_cmdline $core_build_args . -Bbuild" make_cmdline1="$make_cmdline $core_build_args -DCMAKE_BUILD_TYPE=$cmake_build_type . -Bbuild"
make_cmdline2="$make_cmdline --build build/ --target $core_cmake_target --config Release -- " make_cmdline2="$make_cmdline --build build/ --target $core_cmake_target --config $cmake_build_type -- "
[ -n "$JOBS" ] && make_cmdline2="$make_cmdline2 -j$JOBS" [ -n "$JOBS" ] && make_cmdline2="$make_cmdline2 -j$JOBS"
[ -n "$DEBUG" ] && make_cmdline2="$make_cmdline2 DEBUG=$DEBUG"
$core_build_prebuild $core_build_prebuild
echo_cmd "$make_cmdline1" echo_cmd "$make_cmdline1"