Allow multiple resource contexts of the same type. IHNM has serveral

different voice files, presumably one for each section of the game plus one
for shared voices. The getContext() function takes an optional second
parameter to indicate which of the resource files is requested.

svn-id: r18575
This commit is contained in:
Torbjörn Andersson 2005-07-23 15:23:01 +00:00
parent a641c3add7
commit 71436ff1de
2 changed files with 15 additions and 7 deletions

View File

@ -133,7 +133,7 @@ bool Resource::loadContext(ResourceContext *context) {
}
bool Resource::createContexts() {
int i, j;
int i;
ResourceContext *context;
_contextsCount = _vm->getGameDescription()->filesCount;
_contexts = (ResourceContext*)calloc(_contextsCount, sizeof(*_contexts));
@ -143,11 +143,18 @@ bool Resource::createContexts() {
context->file = new Common::File();
context->fileName = _vm->getGameDescription()->filesDescriptions[i].fileName;
context->fileType = _vm->getGameDescription()->filesDescriptions[i].fileType;
context->serial = 0;
//self check
for (j = 0; j < i; j++) {
if ((_contexts[j].fileType & context->fileType) != 0) {
error("Resource::createContexts() duplicate fileType");
// IHNM has serveral different voice files, so we need to allow
// multiple resource contexts of the same type. We tell them
// apart by assigning each of the duplicates an unique serial
// number. The default behaviour when requesting a context will
// be to look for serial number 0.
for (int j = i - 1; j >= 0; j--) {
if (_contexts[j].fileType & context->fileType) {
context->serial = _contexts[j].serial + 1;
break;
}
}

View File

@ -48,6 +48,7 @@ struct ResourceContext {
const char *fileName;
uint16 fileType;
Common::File *file;
int serial;
bool isBigEndian;
ResourceData *table;
@ -72,10 +73,10 @@ public:
size_t getResourceSize(ResourceContext *context, uint32 resourceId);
uint32 convertResourceId(uint32 resourceId);
ResourceContext *getContext(uint16 fileType) {
ResourceContext *getContext(uint16 fileType, int serial = 0) {
int i;
for (i = 0; i < _contextsCount; i++) {
if (_contexts[i].fileType & fileType) {
if ((_contexts[i].fileType & fileType) && _contexts[i].serial == serial) {
return &_contexts[i];
}
}