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BugFix:Number.parseFloat("10000000000000000000000.0") Get an error result
modify NumberHelper::StringToDouble , set exponent 0 in step 8. parse '.' issue:https://gitee.com/openharmony/arkcompiler_ets_runtime/issues/I8D716 Signed-off-by: hecunmao <hecunmao@huawei.com> Change-Id: Ic5f1a2cfdc9ee04a12b328f72e153be949a639ee
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@ -609,6 +609,7 @@ double NumberHelper::StringToDouble(const uint8_t *start, const uint8_t *end, ui
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}
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// 8. parse '.'
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exponent = 0;
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if (radix == DECIMAL && *p == '.') {
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RETURN_IF_CONVERSION_END(++p, end, (digits > 0 || (digits == 0 && leadingZero)) ?
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(number * std::pow(radix, exponent)) : NAN_VALUE);
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@ -109,4 +109,7 @@ print(s)
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print(Number.parseInt("4294967294"))
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print(Number.parseInt("2147483648"))
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print(Number.parseFloat("10000000000000000000000.0"));
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print("builtins number end");
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@ -99,6 +99,7 @@ TypeError: Cannot convert a BigInt value to a number
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0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000034lmua2oev
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4294967294
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2147483648
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1e+22
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builtins number end
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builtins regexp start
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20210608_5V0J5lVh4xVNYx0AUE.jpg,.jpg
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