third_party_ffmpeg/libavformat/urldecode.c
Antti Seppälä 5423e908c9 Support urlencoded http authentication credentials
It should be possible to specify usernames in http requests containing
urlencoded characters. This patch adds support for decoding the auth
strings.

Signed-off-by: Antti Seppälä <a.seppala@gmail.com>
Signed-off-by: Martin Storsjö <martin@martin.st>
2012-07-26 00:18:32 +03:00

88 lines
2.3 KiB
C

/*
* Simple URL decoding function
* Copyright (c) 2012 Antti Seppälä
*
* References:
* RFC 3986: Uniform Resource Identifier (URI): Generic Syntax
* T. Berners-Lee et al. The Internet Society, 2005
*
* based on http://www.icosaedro.it/apache/urldecode.c
* from Umberto Salsi (salsi@icosaedro.it)
*
* This file is part of Libav.
*
* Libav is free software; you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation; either
* version 2.1 of the License, or (at your option) any later version.
*
* Libav is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with Libav; if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
*/
#include <ctype.h>
#include <string.h>
#include "libavutil/mem.h"
#include "libavutil/avstring.h"
#include "urldecode.h"
char *ff_urldecode(const char *url)
{
int s = 0, d = 0, url_len = 0;
char c;
char *dest = NULL;
if (!url)
return NULL;
url_len = strlen(url) + 1;
dest = av_malloc(url_len);
if (!dest)
return NULL;
while (s < url_len) {
c = url[s++];
if (c == '%' && s + 2 < url_len) {
char c2 = url[s++];
char c3 = url[s++];
if (isxdigit(c2) && isxdigit(c3)) {
c2 = av_tolower(c2);
c3 = av_tolower(c3);
if (c2 <= '9')
c2 = c2 - '0';
else
c2 = c2 - 'a' + 10;
if (c3 <= '9')
c3 = c3 - '0';
else
c3 = c3 - 'a' + 10;
dest[d++] = 16 * c2 + c3;
} else { /* %zz or something other invalid */
dest[d++] = c;
dest[d++] = c2;
dest[d++] = c3;
}
} else if (c == '+') {
dest[d++] = ' ';
} else {
dest[d++] = c;
}
}
return dest;
}