Help: Clarify cmake_host_system_information memory units

The memory size query implementations report in units of one mebibyte
(2^20).  Clarify the unit in the documentation because "megabyte" might
also be interpreted as 10^6.
This commit is contained in:
Taylor Holberton 2018-09-02 10:16:56 -04:00 committed by Craig Scott
parent d5a12cc84d
commit 228a2b0d82

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@ -20,10 +20,10 @@ Key Description
``NUMBER_OF_PHYSICAL_CORES`` Number of physical cores
``HOSTNAME`` Hostname
``FQDN`` Fully qualified domain name
``TOTAL_VIRTUAL_MEMORY`` Total virtual memory in megabytes
``AVAILABLE_VIRTUAL_MEMORY`` Available virtual memory in megabytes
``TOTAL_PHYSICAL_MEMORY`` Total physical memory in megabytes
``AVAILABLE_PHYSICAL_MEMORY`` Available physical memory in megabytes
``TOTAL_VIRTUAL_MEMORY`` Total virtual memory in MiB [#mebibytes]_
``AVAILABLE_VIRTUAL_MEMORY`` Available virtual memory in MiB [#mebibytes]_
``TOTAL_PHYSICAL_MEMORY`` Total physical memory in MiB [#mebibytes]_
``AVAILABLE_PHYSICAL_MEMORY`` Available physical memory in MiB [#mebibytes]_
``IS_64BIT`` One if processor is 64Bit
``HAS_FPU`` One if processor has floating point unit
``HAS_MMX`` One if processor supports MMX instructions
@ -44,3 +44,7 @@ Key Description
``OS_VERSION`` The OS build ID
``OS_PLATFORM`` See :variable:`CMAKE_HOST_SYSTEM_PROCESSOR`
============================= ================================================
.. rubric:: Footnotes
.. [#mebibytes] One MiB (mebibyte) is equal to 1024x1024 bytes.