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Help: Clarify cmake_host_system_information memory units
The memory size query implementations report in units of one mebibyte (2^20). Clarify the unit in the documentation because "megabyte" might also be interpreted as 10^6.
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@ -20,10 +20,10 @@ Key Description
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``NUMBER_OF_PHYSICAL_CORES`` Number of physical cores
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``HOSTNAME`` Hostname
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``FQDN`` Fully qualified domain name
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``TOTAL_VIRTUAL_MEMORY`` Total virtual memory in megabytes
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``AVAILABLE_VIRTUAL_MEMORY`` Available virtual memory in megabytes
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``TOTAL_PHYSICAL_MEMORY`` Total physical memory in megabytes
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``AVAILABLE_PHYSICAL_MEMORY`` Available physical memory in megabytes
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``TOTAL_VIRTUAL_MEMORY`` Total virtual memory in MiB [#mebibytes]_
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``AVAILABLE_VIRTUAL_MEMORY`` Available virtual memory in MiB [#mebibytes]_
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``TOTAL_PHYSICAL_MEMORY`` Total physical memory in MiB [#mebibytes]_
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``AVAILABLE_PHYSICAL_MEMORY`` Available physical memory in MiB [#mebibytes]_
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``IS_64BIT`` One if processor is 64Bit
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``HAS_FPU`` One if processor has floating point unit
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``HAS_MMX`` One if processor supports MMX instructions
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@ -44,3 +44,7 @@ Key Description
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``OS_VERSION`` The OS build ID
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``OS_PLATFORM`` See :variable:`CMAKE_HOST_SYSTEM_PROCESSOR`
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============================= ================================================
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.. rubric:: Footnotes
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.. [#mebibytes] One MiB (mebibyte) is equal to 1024x1024 bytes.
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