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Use 8-byte alignment for FixedSizeAllocatorWithCleanup when 16-byte alignment is false (GH #992)

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Jeffrey Walton 2020-12-29 01:49:17 -05:00
parent 9fe5ccfbee
commit 4bc7408ae2
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1 changed files with 14 additions and 4 deletions
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18
secblock.h
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@ -547,9 +547,14 @@ private:
#else
// CRYPTOPP_BOOL_ALIGN16 is 0. Use natural alignment of T.
// CRYPTOPP_BOOL_ALIGN16 is 0. Normally we would use the natural
// alignment of T. The problem we are having is, some toolchains
// are changing the boundary for 64-bit arrays. 64-bit elements
// require 8-byte alignment, but the toolchain is laying the array
// out on a 4 byte boundary. See GH #992 for mystery alignment:
// https://github.com/weidai11/cryptopp/issues/992
T* GetAlignedArray() {return m_array;}
T m_array[S];
CRYPTOPP_ALIGN_DATA(8) T m_array[S];
#endif
@ -700,9 +705,14 @@ public:
private:
// T_Align16 is false. Use natural alignment of T.
// T_Align16 is false. Normally we would use the natural
// alignment of T. The problem we are having is, some toolchains
// are changing the boundary for 64-bit arrays. 64-bit elements
// require 8-byte alignment, but the toolchain is laying the array
// out on a 4 byte boundary. See GH #992 for mystery alignment:
// https://github.com/weidai11/cryptopp/issues/992
T* GetAlignedArray() {return m_array;}
T m_array[S];
CRYPTOPP_ALIGN_DATA(8) T m_array[S];
A m_fallbackAllocator;
bool m_allocated;