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Fixed Asan and UBsan detection for non-x86

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This commit is contained in:
Jeffrey Walton 2016-01-08 15:11:21 -05:00
parent ee23865b77
commit c299c4ba1a
1 changed files with 5 additions and 4 deletions
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9
cryptest.sh
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@ -38,7 +38,8 @@ IS_LINUX=$(uname -s | grep -i -c linux)
IS_CYGWIN=$(uname -s | grep -i -c cygwin)
IS_MINGW=$(uname -s | grep -i -c mingw)
IS_OPENBSD=$(uname -s | grep -i -c openbsd)
IS_INTEL=$(uname -m | egrep -i -c "(i386|i586|i686|amd64|x86_64)")
IS_X86=$(uname -m | egrep -i -c "(i386|i586|i686|amd64|x86_64)")
IS_X64=$(uname -m | egrep -i -c "(amd64|x86_64)")
IS_PPC=$(uname -m | egrep -i -c "(Power|PPC)")
# We need to use the C++ compiler to determine if c++11 is available. Otherwise
@ -93,7 +94,7 @@ fi
# Set to 0 if you don't have UBsan
$CXX -x c++ -fsanitize=undefined adhoc.cpp.proto -c -o $TMP/adhoc > /dev/null 2>&1
if [ "$?" -eq "0" ]; then
if [ "$?" -eq "0" ] && [ "$IS_X86" -ne "0" ]; then
HAVE_UBSAN=1
else
HAVE_UBSAN=0
@ -101,7 +102,7 @@ fi
# Set to 0 if you don't have Asan
$CXX -x c++ -fsanitize=undefined adhoc.cpp.proto -c -o $TMP/adhoc > /dev/null 2>&1
if [ "$?" -eq "0" ]; then
if [ "$?" -eq "0" ] && [ "$IS_X86" -ne "0" ]; then
HAVE_ASAN=1
else
HAVE_ASAN=0
@ -121,7 +122,7 @@ fi
# Set to 0 if you don't have Intel multiarch
HAVE_INTEL_MULTIARCH=0
if [ "$IS_DARWIN" -ne "0" ] && [ "$IS_INTEL" -ne "0" ]; then
if [ "$IS_DARWIN" -ne "0" ] && [ "$IS_X86" -ne "0" ]; then
$CXX -x c++ -arch i386 -arch x86_64 -c adhoc.cpp.proto -c -o $TMP/adhoc > /dev/null 2>&1
if [ "$?" -eq "0" ]; then
HAVE_INTEL_MULTIARCH=1