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rcu: handle forks safely

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After forking, only the calling thread is duplicated in the child process.
The call_rcu thread has to be recreated in the child.  Exploit the fact
that only one thread exists (same as when constructors run), and just redo
the entire initialization to ensure the threads are in the proper state.

The only additional things to do are emptying the list of threads
registered with RCU, and unlocking the lock that was taken in the prepare
callback (implementations are allowed to fail pthread_mutex_init()
if the mutex is still locked).

Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
This commit is contained in:
Paolo Bonzini 2015-03-05 16:53:48 +01:00
parent 24fa90499f
commit 21b7cf9e07
1 changed files with 32 additions and 1 deletions
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33
util/rcu.c
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@ -283,7 +283,7 @@ void rcu_unregister_thread(void)
qemu_mutex_unlock(&rcu_gp_lock);
}
static void __attribute__((__constructor__)) rcu_init(void)
static void rcu_init_complete(void)
{
QemuThread thread;
@ -291,8 +291,39 @@ static void __attribute__((__constructor__)) rcu_init(void)
qemu_event_init(&rcu_gp_event, true);
qemu_event_init(&rcu_call_ready_event, false);
/* The caller is assumed to have iothread lock, so the call_rcu thread
* must have been quiescent even after forking, just recreate it.
*/
qemu_thread_create(&thread, "call_rcu", call_rcu_thread,
NULL, QEMU_THREAD_DETACHED);
rcu_register_thread();
}
#ifdef CONFIG_POSIX
static void rcu_init_lock(void)
{
qemu_mutex_lock(&rcu_gp_lock);
}
static void rcu_init_unlock(void)
{
qemu_mutex_unlock(&rcu_gp_lock);
}
static void rcu_init_child(void)
{
qemu_mutex_unlock(&rcu_gp_lock);
memset(&registry, 0, sizeof(registry));
rcu_init_complete();
}
#endif
static void __attribute__((__constructor__)) rcu_init(void)
{
#ifdef CONFIG_POSIX
pthread_atfork(rcu_init_lock, rcu_init_unlock, rcu_init_child);
#endif
rcu_init_complete();
}