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block: use the request length for iov alignment

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An iov length needs to be aligned to the logical block size, which may
be larger than the memory alignment.

Tested-by: Jens Axboe <axboe@kernel.dk>
Signed-off-by: Keith Busch <kbusch@kernel.org>
Message-Id: <20220929200523.3218710-3-kbusch@meta.com>
Reviewed-by: Kevin Wolf <kwolf@redhat.com>
Signed-off-by: Kevin Wolf <kwolf@redhat.com>
This commit is contained in:
Keith Busch 2022-09-29 13:05:23 -07:00 committed by Kevin Wolf
parent a7c5f67a78
commit 25474d90aa
1 changed files with 2 additions and 1 deletions
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3
block/file-posix.c
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@ -2068,13 +2068,14 @@ static bool bdrv_qiov_is_aligned(BlockDriverState *bs, QEMUIOVector *qiov)
{
int i;
size_t alignment = bdrv_min_mem_align(bs);
size_t len = bs->bl.request_alignment;
IO_CODE();
for (i = 0; i < qiov->niov; i++) {
if ((uintptr_t) qiov->iov[i].iov_base % alignment) {
return false;
}
if (qiov->iov[i].iov_len % alignment) {
if (qiov->iov[i].iov_len % len) {
return false;
}
}