multifd: Unconditionally unregister yank function

To: qemu-devel <qemu-devel@nongnu.org>
Cc: "Dr. David Alan Gilbert" <dgilbert@redhat.com>, Juan Quintela
 <quintela@redhat.com>, Peter Xu <peterx@redhat.com>, Leonardo Bras Soares
 Passos <lsoaresp@redhat.com>
Date: Wed, 4 Aug 2021 21:26:32 +0200 (5 weeks, 11 hours, 52 minutes ago)

[[PGP Signed Part:No public key for 35AB0B289C5DB258 created at 2021-08-04T21:26:32+0200 using RSA]]
Unconditionally unregister yank function in multifd_load_cleanup().
If it is not unregistered here, it will leak and cause a crash
in yank_unregister_instance(). Now if the ioc is still in use
afterwards, it will only lead to qemu not being able to recover
from a hang related to that ioc.

After checking the code, i am pretty sure that ref is always 1
when arriving here. So all this currently does is remove the
unneeded check.

Signed-off-by: Lukas Straub <lukasstraub2@web.de>
Reviewed-by: Juan Quintela <quintela@redhat.com>
Signed-off-by: Juan Quintela <quintela@redhat.com>
This commit is contained in:
Lukas Straub 2021-09-09 09:19:45 +02:00 committed by Juan Quintela
parent 20171ea895
commit e9ab82b858

View File

@ -991,10 +991,7 @@ int multifd_load_cleanup(Error **errp)
for (i = 0; i < migrate_multifd_channels(); i++) {
MultiFDRecvParams *p = &multifd_recv_state->params[i];
if (OBJECT(p->c)->ref == 1) {
migration_ioc_unregister_yank(p->c);
}
migration_ioc_unregister_yank(p->c);
object_unref(OBJECT(p->c));
p->c = NULL;
qemu_mutex_destroy(&p->mutex);