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configure: Add -Werror to PIE probe
Without -Werror, the probe may succeed, but then compilation fails later when -Werror is added for other reasons. Shows up on windows, where the compiler complains about -fPIC. Signed-off-by: Richard Henderson <richard.henderson@linaro.org> Signed-off-by: Alex Bennée <alex.bennee@linaro.org> Reviewed-by: Philippe Mathieu-Daudé <philmd@redhat.com> Tested-by: Philippe Mathieu-Daudé <philmd@redhat.com> Message-Id: <20200401214756.6559-1-richard.henderson@linaro.org> Message-Id: <20200403191150.863-13-alex.bennee@linaro.org>
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configure
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configure
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@ -2119,7 +2119,7 @@ if compile_prog "-Werror -fno-pie" "-no-pie"; then
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fi
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if test "$static" = "yes"; then
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if test "$pie" != "no" && compile_prog "-fPIE -DPIE" "-static-pie"; then
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if test "$pie" != "no" && compile_prog "-Werror -fPIE -DPIE" "-static-pie"; then
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QEMU_CFLAGS="-fPIE -DPIE $QEMU_CFLAGS"
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QEMU_LDFLAGS="-static-pie $QEMU_LDFLAGS"
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pie="yes"
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@ -2132,7 +2132,7 @@ if test "$static" = "yes"; then
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elif test "$pie" = "no"; then
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QEMU_CFLAGS="$CFLAGS_NOPIE $QEMU_CFLAGS"
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QEMU_LDFLAGS="$LDFLAGS_NOPIE $QEMU_LDFLAGS"
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elif compile_prog "-fPIE -DPIE" "-pie"; then
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elif compile_prog "-Werror -fPIE -DPIE" "-pie"; then
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QEMU_CFLAGS="-fPIE -DPIE $QEMU_CFLAGS"
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QEMU_LDFLAGS="-pie $QEMU_LDFLAGS"
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pie="yes"
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