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79761c6681
Fix following bugs in "fallback implementation of counting semaphores with mutex+condvar" added in c166cb72f1676855816340666c3b618beef4b976: - waiting threads are not restarted properly if more than one threads are waiting unblock signals in qemu_sem_timedwait() - possible missing pthread_cond_signal(3) calls when waiting threads are returned by ETIMEDOUT - fix an uninitialized variable The problem is analyzed by and fix is provided by Noriyuki Soda. Also put additional cleanup suggested by Laszlo Ersek: - make QemuSemaphore.count unsigned (it won't be negative) - check a return value of in pthread_cond_wait() in qemu_sem_wait() Signed-off-by: Izumi Tsutsui <tsutsui@ceres.dti.ne.jp> Reviewed-by: Laszlo Ersek <lersek@redhat.com> Message-id: 1372841894-10634-1-git-send-email-tsutsui@ceres.dti.ne.jp Signed-off-by: Anthony Liguori <aliguori@us.ibm.com>
29 lines
432 B
C
29 lines
432 B
C
#ifndef __QEMU_THREAD_POSIX_H
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#define __QEMU_THREAD_POSIX_H 1
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#include "pthread.h"
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#include <semaphore.h>
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struct QemuMutex {
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pthread_mutex_t lock;
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};
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struct QemuCond {
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pthread_cond_t cond;
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};
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struct QemuSemaphore {
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#if defined(__APPLE__) || defined(__NetBSD__)
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pthread_mutex_t lock;
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pthread_cond_t cond;
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unsigned int count;
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#else
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sem_t sem;
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#endif
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};
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struct QemuThread {
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pthread_t thread;
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};
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#endif
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