sched: Don't initialize alloc_state in build_sched_domains()

alloc_state will be overwritten by __visit_domain_allocation_hell() and so we
don't actually need to initialize alloc_state.

Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
Signed-off-by: Peter Zijlstra <peterz@infradead.org>
Link: http://lkml.kernel.org/r/df57734a075cc5ad130e1ae498702e24f2529ab8.1370861520.git.viresh.kumar@linaro.org
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Viresh Kumar 2013-06-10 16:27:18 +05:30 committed by Ingo Molnar
parent 22da956953
commit 1c63216940

View File

@ -5969,7 +5969,7 @@ struct sched_domain *build_sched_domain(struct sched_domain_topology_level *tl,
static int build_sched_domains(const struct cpumask *cpu_map, static int build_sched_domains(const struct cpumask *cpu_map,
struct sched_domain_attr *attr) struct sched_domain_attr *attr)
{ {
enum s_alloc alloc_state = sa_none; enum s_alloc alloc_state;
struct sched_domain *sd; struct sched_domain *sd;
struct s_data d; struct s_data d;
int i, ret = -ENOMEM; int i, ret = -ENOMEM;