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Fix a LDRT/LDRBT decoding bug where for Encoding A2, if Inst{4} != 0, we should reject the instruction
as invalid. llvm-svn: 128734
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@ -1106,6 +1106,14 @@ static bool DisassembleLdStFrm(MCInst &MI, unsigned Opcode, uint32_t insn,
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MI.addOperand(MCOperand::CreateImm(Offset));
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OpIdx += 1;
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} else {
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// The opcode ARM::LDRT actually corresponds to both Encoding A1 and A2 of
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// A8.6.86 LDRT. So if Inst{4} != 0 while Inst{25} (getIBit(insn)) == 1,
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// we should reject this insn as invalid.
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//
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// Ditto for LDRBT.
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if ((Opcode == ARM::LDRT || Opcode == ARM::LDRBT) && (slice(insn,4,4) == 1))
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return false;
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// Disassemble the offset reg (Rm), shift type, and immediate shift length.
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MI.addOperand(MCOperand::CreateReg(getRegisterEnum(B, ARM::GPRRegClassID,
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decodeRm(insn))));
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@ -45,6 +45,9 @@
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# CHECK: ldr r0, [r2], #15
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0x0f 0x00 0x92 0xe4
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# CHECK: ldr r5, [r7, -r10, lsl #2]
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0x0a 0x51 0x17 0xe7
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# CHECK: ldrh r0, [r2], #0
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0xb0 0x00 0xd2 0xe0
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12
test/MC/Disassembler/ARM/invalid-LDRT-arm.txt
Normal file
12
test/MC/Disassembler/ARM/invalid-LDRT-arm.txt
Normal file
@ -0,0 +1,12 @@
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# RUN: llvm-mc --disassemble %s -triple=arm-apple-darwin9 |& grep {invalid instruction encoding}
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# Opcode=0 Name=PHI Format=(42)
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# 31 30 29 28 27 26 25 24 23 22 21 20 19 18 17 16 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0
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# -------------------------------------------------------------------------------------------------
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# | 1: 1: 1: 0| 0: 1: 1: 0| 0: 0: 1: 1| 0: 1: 1: 1| 0: 1: 0: 1| 0: 0: 0: 1| 0: 0: 0: 1| 0: 0: 0: 0|
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# -------------------------------------------------------------------------------------------------
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#
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# The bytes have Inst{4} = 1, so it's not an LDRT Encoding A2 instruction.
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0x10 0x51 0x37 0xe6
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