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if functiontype is going to have a pointer to a paramattr object, it better

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be const.  The only way to get a pointer to these returns a const pointer.

llvm-svn: 36734
This commit is contained in:
Chris Lattner 2007-05-04 03:39:28 +00:00
parent 68ab99ffb6
commit da3b0264f7
2 changed files with 5 additions and 5 deletions
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6
include/llvm/DerivedTypes.h
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@ -140,12 +140,12 @@ public:
class FunctionType : public DerivedType {
friend class TypeMap<FunctionValType, FunctionType>;
bool isVarArgs;
ParamAttrsList *ParamAttrs;
const ParamAttrsList *ParamAttrs;
FunctionType(const FunctionType &); // Do not implement
const FunctionType &operator=(const FunctionType &); // Do not implement
FunctionType(const Type *Result, const std::vector<const Type*> &Params,
bool IsVarArgs, ParamAttrsList *Attrs = 0);
bool IsVarArgs, const ParamAttrsList *Attrs = 0);
public:
/// FunctionType::get - This static method is the primary way of constructing
@ -155,7 +155,7 @@ public:
const Type *Result, ///< The result type
const std::vector<const Type*> &Params, ///< The types of the parameters
bool isVarArg, ///< Whether this is a variable argument length function
ParamAttrsList *Attrs = 0
const ParamAttrsList *Attrs = 0
///< Indicates the parameter attributes to use, if any. The 0th entry
///< in the list refers to the return type. Parameters are numbered
///< starting at 1. This argument must be on the heap and FunctionType

4
lib/VMCore/Type.cpp
View File

@ -417,7 +417,7 @@ const IntegerType *Type::Int64Ty = new BuiltinIntegerType(64);
FunctionType::FunctionType(const Type *Result,
const std::vector<const Type*> &Params,
bool IsVarArgs, ParamAttrsList *Attrs)
bool IsVarArgs, const ParamAttrsList *Attrs)
: DerivedType(FunctionTyID), isVarArgs(IsVarArgs), ParamAttrs(Attrs) {
ContainedTys = reinterpret_cast<PATypeHandle*>(this+1);
NumContainedTys = Params.size() + 1; // + 1 for result type
@ -1084,7 +1084,7 @@ FunctionValType FunctionValType::get(const FunctionType *FT) {
FunctionType *FunctionType::get(const Type *ReturnType,
const std::vector<const Type*> &Params,
bool isVarArg,
ParamAttrsList *Attrs) {
const ParamAttrsList *Attrs) {
FunctionValType VT(ReturnType, Params, isVarArg, Attrs);
FunctionType *FT = FunctionTypes->get(VT);