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107 lines
3.9 KiB
C++
107 lines
3.9 KiB
C++
//===-- Value.cpp - Implement the Value class -----------------------------===//
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//
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// The LLVM Compiler Infrastructure
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//
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// This file was developed by the LLVM research group and is distributed under
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// the University of Illinois Open Source License. See LICENSE.TXT for details.
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//
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//===----------------------------------------------------------------------===//
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//
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// This file implements the Value and User classes.
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//
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//===----------------------------------------------------------------------===//
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#include "llvm/InstrTypes.h"
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#include "llvm/SymbolTable.h"
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#include "llvm/DerivedTypes.h"
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#include "llvm/Constant.h"
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#include "Support/LeakDetector.h"
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#include <algorithm>
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#include <iostream>
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using namespace llvm;
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//===----------------------------------------------------------------------===//
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// Value Class
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//===----------------------------------------------------------------------===//
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static inline const Type *checkType(const Type *Ty) {
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assert(Ty && "Value defined with a null type: Error!");
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return Ty;
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}
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Value::Value(const Type *ty, unsigned scid, const std::string &name)
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: SubclassID(scid), Ty(checkType(ty)), Name(name) {
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}
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Value::~Value() {
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#ifndef NDEBUG // Only in -g mode...
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// Check to make sure that there are no uses of this value that are still
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// around when the value is destroyed. If there are, then we have a dangling
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// reference and something is wrong. This code is here to print out what is
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// still being referenced. The value in question should be printed as
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// a <badref>
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//
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if (Uses.begin() != Uses.end()) {
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std::cerr << "While deleting: " << *Ty << "%" << Name << "\n";
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for (use_const_iterator I = Uses.begin(), E = Uses.end(); I != E; ++I)
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std::cerr << "Use still stuck around after Def is destroyed:"
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<< **I << "\n";
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}
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#endif
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assert(Uses.begin() == Uses.end() &&"Uses remain when a value is destroyed!");
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// There should be no uses of this object anymore, remove it.
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LeakDetector::removeGarbageObject(this);
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}
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// uncheckedReplaceAllUsesWith - This is exactly the same as replaceAllUsesWith,
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// except that it doesn't have all of the asserts. The asserts fail because we
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// are half-way done resolving types, which causes some types to exist as two
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// different Type*'s at the same time. This is a sledgehammer to work around
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// this problem.
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//
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void Value::uncheckedReplaceAllUsesWith(Value *New) {
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while (!Uses.empty()) {
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Use &U = Uses.back();
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// Must handle Constants specially, we cannot call replaceUsesOfWith on a
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// constant!
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if (Constant *C = dyn_cast<Constant>(U.getUser())) {
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C->replaceUsesOfWithOnConstant(this, New, true);
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} else {
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U.set(New);
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}
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}
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}
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void Value::replaceAllUsesWith(Value *New) {
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assert(New && "Value::replaceAllUsesWith(<null>) is invalid!");
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assert(New != this && "this->replaceAllUsesWith(this) is NOT valid!");
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assert(New->getType() == getType() &&
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"replaceAllUses of value with new value of different type!");
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uncheckedReplaceAllUsesWith(New);
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}
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//===----------------------------------------------------------------------===//
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// User Class
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//===----------------------------------------------------------------------===//
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// replaceUsesOfWith - Replaces all references to the "From" definition with
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// references to the "To" definition.
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//
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void User::replaceUsesOfWith(Value *From, Value *To) {
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if (From == To) return; // Duh what?
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assert(!isa<Constant>(this) &&
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"Cannot call User::replaceUsesofWith on a constant!");
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for (unsigned i = 0, E = getNumOperands(); i != E; ++i)
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if (getOperand(i) == From) { // Is This operand is pointing to oldval?
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// The side effects of this setOperand call include linking to
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// "To", adding "this" to the uses list of To, and
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// most importantly, removing "this" from the use list of "From".
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setOperand(i, To); // Fix it now...
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}
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}
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