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- Eliminate redundant successors. - Convert an indirectbr with one successor into a direct branch. Also, generalize SimplifyCFG to be able to be run on a function entry block. It knows quite a few simplifications which are applicable to the entry block, and it only needs a few checks to avoid trouble with the entry block. llvm-svn: 111060
52 lines
1.3 KiB
LLVM
52 lines
1.3 KiB
LLVM
; RUN: opt -S -simplifycfg < %s | FileCheck %s
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; SimplifyCFG should eliminate redundant indirectbr edges.
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; CHECK: indbrtest0
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; CHECK: indirectbr i8* %t, [label %BB0, label %BB1, label %BB2]
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; CHECK: %x = phi i32 [ 0, %BB0 ], [ 1, %entry ]
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declare void @foo()
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declare void @A()
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declare void @B(i32)
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declare void @C()
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define void @indbrtest0(i8** %P, i8** %Q) {
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entry:
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store i8* blockaddress(@indbrtest0, %BB0), i8** %P
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store i8* blockaddress(@indbrtest0, %BB1), i8** %P
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store i8* blockaddress(@indbrtest0, %BB2), i8** %P
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call void @foo()
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%t = load i8** %Q
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indirectbr i8* %t, [label %BB0, label %BB1, label %BB2, label %BB0, label %BB1, label %BB2]
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BB0:
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call void @A()
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br label %BB1
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BB1:
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%x = phi i32 [ 0, %BB0 ], [ 1, %entry ], [ 1, %entry ]
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call void @B(i32 %x)
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ret void
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BB2:
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call void @C()
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ret void
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}
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; SimplifyCFG should convert the indirectbr into a directbr. It would be even
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; better if it removed the branch altogether, but simplifycfdg currently misses
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; that because the predecessor is the entry block.
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; CHECK: indbrtest1
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; CHECK: br label %BB0
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define void @indbrtest1(i8** %P, i8** %Q) {
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entry:
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store i8* blockaddress(@indbrtest1, %BB0), i8** %P
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call void @foo()
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%t = load i8** %Q
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indirectbr i8* %t, [label %BB0, label %BB0]
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BB0:
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call void @A()
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ret void
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}
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