llvm/test/MC/Hexagon/new-value-check.s
2016-05-20 14:01:34 +00:00

73 lines
2.2 KiB
ArmAsm

# RUN: not llvm-mc -triple=hexagon < %s 2>&1 | \
# RUN: FileCheck %s --check-prefix=CHECK-STRICT
# RUN: not llvm-mc -triple=hexagon -relax-nv-checks < %s 2>&1 | \
# RUN: FileCheck %s --check-prefix=CHECK-RELAXED
# CHECK-STRICT: :12:1: error: register `R0' used with `.new' but not validly modified in the same packet
# CHECK-RELAXED: :12:1: error: register `R0' used with `.new' but not validly modified in the same packet
{
# invalid: r0 definition predicated on the opposite condition
if (p3) r0 = add(r1, r2)
if (!p3) memb(r20) = r0.new
}
# CHECK-STRICT: :20:1: error: register `R0' used with `.new' but not validly modified in the same packet
# CHECK-RELAXED: :20:1: error: register `R0' used with `.new' but not validly modified in the same packet
{
# invalid: new-value compare-and-jump cannot use floating point value
r0 = sfadd(r1, r2)
if (cmp.eq(r0.new, #0)) jump:nt .
}
# CHECK-STRICT: :29:1: error: register `R0' used with `.new' but not validly modified in the same packet
# CHECK-RELAXED: :29:1: error: register `R0' used with `.new' but not validly modified in the same packet
{
# invalid: definition of r0 should be unconditional (not explicitly docu-
# mented)
if (p0) r0 = r1
if (cmp.eq(r0.new, #0)) jump:nt .
}
# No errors from this point on with the relaxed checks.
# CHECK-RELAXED-NOT: error
# CHECK-STRICT: :41:1: error: register `R0' used with `.new' but not validly modified in the same packet
{
# valid (relaxed): p2 and p3 cannot be proven to violate the new-value
# requirements
if (p3) r0 = add(r1, r2)
if (p2) memb(r20) = r0.new
}
# CHECK-STRICT: :48:1: error: register `R0' used with `.new' but not validly modified in the same packet
{
# valid (relaxed): p3 could be always true
if (p3) r0 = add(r1, r2)
memb(r20) = r0.new
}
# No errors from this point on with the strict checks.
# CHECK-RELAXED-NOT: error
{
# valid: r0 defined unconditionally
r0 = add(r1, r2)
if (p2) memb(r20) = r0.new
}
{
# valid: r0 definition and use identically predicated
if (p3) r0 = add(r1, r2)
if (p3) memb(r20) = r0.new
}
{
# valid: r0 defined regardless of p0
if (p0) r0 = #0
if (!p0) r0 = #1
if (p0) memb(r20) = r0.new
}