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[AMDGPU] Correct the handling of inlineasm output registers.
Summary: - There's a regression due to the cross-block RC assignment. Use the proper way to derive the output register RC in inline asm. Reviewers: rampitec, alex-t Subscribers: arsenm, kzhuravl, jvesely, wdng, nhaehnle, dstuttard, tpr, t-tye, eraman, hiraditya, llvm-commits, yaxunl Tags: #llvm Differential Revision: https://reviews.llvm.org/D62537 llvm-svn: 361868
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@ -10244,8 +10244,7 @@ bool SITargetLowering::requiresUniformRegister(MachineFunction &MF,
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unsigned AssignedReg;
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const TargetRegisterClass *RC;
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std::tie(AssignedReg, RC) = getRegForInlineAsmConstraint(
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SIRI, TC.ConstraintCode,
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getSimpleValueType(MF.getDataLayout(), CS.getType()));
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SIRI, TC.ConstraintCode, TC.ConstraintVT);
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if (RC) {
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MachineRegisterInfo &MRI = MF.getRegInfo();
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if (AssignedReg != 0 && SIRI->isSGPRReg(MRI, AssignedReg))
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@ -277,3 +277,23 @@ entry:
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tail call void asm sideeffect "; sgpr96 $0", "s"(<3 x i32> <i32 10, i32 11, i32 12>) #1
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ret void
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}
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; Check aggregate types are handled properly.
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; CHECK-LABEL: mad_u64
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; CHECK: v_mad_u64_u32
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define void @mad_u64(i32 %x) {
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entry:
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br i1 undef, label %exit, label %false
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false:
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%s0 = tail call { i64, i64 } asm sideeffect "v_mad_u64_u32 $0, $1, $2, $3, $4", "=v,=s,v,v,v"(i32 -766435501, i32 %x, i64 0)
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br label %exit
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exit:
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%s1 = phi { i64, i64} [ undef, %entry ], [ %s0, %false]
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%v0 = extractvalue { i64, i64 } %s1, 0
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%v1 = extractvalue { i64, i64 } %s1, 1
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tail call void asm sideeffect "; use $0", "v"(i64 %v0)
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tail call void asm sideeffect "; use $0", "v"(i64 %v1)
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ret void
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}
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